0
$\begingroup$

The following equation is often used to describe the flux at a receiver:

$$F_\nu = \int I_\nu \cos(\theta)\,\mathrm d\Omega.$$

Where $I_\nu$ is the specific intensity.

Could somebody explain with pictures how $d\Omega$ and $\theta$ are defined as seen from the observer?

$\endgroup$

1 Answer 1

0
$\begingroup$

$\theta$ is the angle between the normal vector $\mathbf{\hat{n}}$ of some infinitesimal surface $dA$. The solid angle is then given by $$d\Omega = \sin(\theta)\mathrm{d}\theta \mathrm{d}\phi,$$

where $\theta,\phi$ are just the regular spherical coordinates. We can always write this in this way, but the integral limits can become quite complicated in spherical coordinates, then one should use other coordinates.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.