I am preparing for an undergraduate degree in Physics, with no teacher in sight until October. The textbook I am using to prepare myself, gave me the following exercise about electric current and left me beyond confused. I would really appreciate it if somebody could help out.
The Ammeter reads: 0.48103 Amp
The Voltmeter reads: 119.7959 Volt
The Ammeter reads: 0.47904 Amp
The Voltmeter reads: 120 Volt
The voltage between a and c is identical in both scenarios.
The book asks me to calculate the resistance of the device (R), the resistance of the Ammeter (A) and the resistance of the Voltmeter (V).
The following is my reasoning, and I am dying to find out where my mistake is:
-The difference in voltage between the two readings shows that the tension between b and c is 0.2405 Volt.
-The current shown by the Ammeter in the first scenario is the total current for the system, whereas the current shown by the Ammeter in the second scenario is the current for its own branch only. Therefore the current of the Voltmeter's branch is the total current minus the current of the Ammeter's branch: 0.48103-0.47904 = 0.00199 Ampère.
-The resistance of the device itself can be calculated: the current of its 'branch' is 0.47904, and as I=V/R and V = 119.7595 between a and b, the resistance of the device itself is 250 Ω.
Here I get stuck, and I need to know where my logic fails:
-Regarding the resistance of the Voltmeter, I have the current (0.00199 Ampere), but I have two different voltages, and they seem equally valid to be plugged into the equation I=V/R. In that sense, I would get two different results from the equation R=V/I. Now, resistance is dependent on ρ, L and A, and one could argue that the L changed here. Either way, I am left with the values R = 60301 Ω and R = 601380 Ω.
-Regarding the resistance of the Ammeter, I have the voltage for b-c (0.2405), but I need the current. Here, there are two options for the Current, but - again - they lead to different values for the Resistance (R = 0.5 Ω and 0.502 Ω respectively). However, in this case, there is no logical reason why the resistance would have changed, because there is no reason for ρ, L and A to have changed. Factually speaking, the Voltage is identical in both cases (0.2405), yet the current has changed: looking at I=V/R, that must mean that the resistance has changed, but it makes no sense…