Here I'm gonna talk about capillarity. The liquid inside the beaker as well as the column is water. As water has a tendency to rise in the capillary as shown, doesn't it violate Pascal's law.
At equilibrium when water has risen in the tube, pressure at point A as well as the pressure at water surface which is open to atmosphere will be $1$ $atm$. In turn pressure at point B will be $1$ $atm$ as it is at the same level above the ground as water in beaker ( Pascal's law ). Which means that $P_a-P_b$ is zero but according to Pascal's law it should have been $h\rho g$.
What's wrong then.