1
$\begingroup$

I'm currently learning about Feynman Path Integrals, and I came across the following paragraph:

"Periodic classical orbits will carry a complex phase which will in general average to zero over many orbits. However if the action of a single orbit is 2πh ̄× integer, the phase factor is unity and therefore such orbits will dominate the path integral. This is the Bohr-Sommerfeld quantisation condition."

Why does the action of a single orbit being $2\pi\hbar ̄~\times $ integer make that path dominate the path integral?

$\endgroup$

marked as duplicate by Qmechanic Aug 23 '18 at 7:25

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.