I believe that there are no "gravitons". A mass warps SpaceTime. Anything moving past the mass has it's direction changed by that warping not by the mass. "Freeze" SpaceTime & remove the mass & it's "gravity" and things will still follow the same warped path. Therefore, there is no "force of gravity."


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    $\begingroup$ No, you are wrong, the warped path is due to the existence of the mass if you remove the mass you have flat space time. Beliefs do not have a place in mathematical formulae. $\endgroup$ – anna v Aug 21 '18 at 16:02
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    $\begingroup$ In order to have a question that will not be closed because it is not mainstream physics, focus on the issue of how the gravitons do whatever they are supposed to do (a real question) rather than stating your own beliefs about gravity. $\endgroup$ – Anders Sandberg Aug 21 '18 at 16:28
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    $\begingroup$ Hi, welcome to Physics SE! Unfortunately, non--mainstream questions are considered off-topic here, so there's no point in pitching for theories. $\endgroup$ – user191954 Aug 21 '18 at 16:28
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    $\begingroup$ Gravitons are predicted by the Quantum Field Theory. This theory requires all fields to be quantum. Gravity is not a standard quantum field, the standard QFT does not work for gravity. To unite both theories with "Quantum Gravity", the QFT must be modified. We don't know how. It may be that gravity is quantum in a non-standard way. Or it may be that the QFT must be changed to allow the interaction with non-quantum fields. It sure is hard to explain the gravitational time dilation (the source of gravity) as an exchange of virtual gravitons, but the quantum world is weird enough, so who knows. $\endgroup$ – safesphere Aug 21 '18 at 20:52

We do not know if there are gravitons. There is no experiment that would prove their existence.

Theoretically, it is a good idea to learn about EM forces, and their carriers, the photons. The mediator of EM forces is the photon. Two particles can have EM interaction by exchanging photons.

Photons do not have rest mass, just like gravitons. That explains the long range of both EM and gravitational forces. The same way the mediator of gravitational effects is the graviton. Two particles can have gravitational interaction by exchanging gravitons.

It is not mass but stress-energy that causes gravity. This way, even particles, like the photon, that have no rest mass, can have gravitational effects.

When stress-energy bends spacetime, that is an effect of gravity. You are right that when a photon travels past the Sun, it travels in bent spacetime (because of the Sun's stress-energy).

Even the Earth orbits the Sun in bent spacetime, because of the Sun's stress-energy.

Gravitons, just like photons, travel with speed c in vacuum, when measured locally. Both EM waves and gravitational waves travel at this speed. If you remove the Sun, the Earth would still move along the bent spacetime orbiting the Sun (even if the Sun is not there anymore) for another 8 minutes. After 8 minutes, the effects of gravity from the Sun's stress-energy disappear, and the Earth starts to move out of the solar system.

  • $\begingroup$ There is very much an experiment that would prove their existence (for a certain meaning of "prove"), just not any currently feasible experiment. $\endgroup$ – Javier Aug 21 '18 at 17:19
  • $\begingroup$ A number of ambiguities in your answer. (1) The electromagnetic interactions are mediated by exchanging virtual photons, not real photons. (2) Photons are massless and cannot decay by emitting gravitons. The gravitational field of a photon is created by the gravitons emitted at the photon emission and absorption events, but not by the photon in flight. (3) The Earth is attracted to the instantaneous position of the Sun, but not to its retarded position. If you tow the Sun away (slower than light), the attraction force will always point to the actual position of the Sun with no 8-minute delay. $\endgroup$ – safesphere Aug 21 '18 at 20:43
  • $\begingroup$ @safesphere (1) Correct. Though, I would like to know if you call it an EM interaction if an atom emits a real photon and another atom absorbs it. Do you call that EM interaction? (2) Correct, photons cannot decay by emitting gravitons. Correct that the gravitational field of the photon is created at the emission. I believe that the gravitational field of the photon travels with the photon at speed c. (3) I think I disagree. If you tow the Sun, the Earth will feel that position change of the Sun only 8 minutes delayed. $\endgroup$ – Árpád Szendrei Aug 22 '18 at 0:21
  • $\begingroup$ (1) Yes, I do. This is why I said "ambiguous" instead of "incorrect". I was referring to, "Two particles can have EM interaction by exchanging photons." These photons are usually virtual, because a single massive particle cannot emit or absorb a real massless photon without violating either energy or momentum conservation. On (3) I also could not believe it, but it is true for both gravity and electromagnetism. Not my idea. I'll try to find a link. $\endgroup$ – safesphere Aug 22 '18 at 4:06
  • $\begingroup$ This is the link I was thinking about: "The attraction toward an object moving with a steady velocity is towards its instantaneous position with no delay, for both gravity and electric charge." See the answer by hawkeye among others here: physics.stackexchange.com/questions/5456/… - Also another one: physics.stackexchange.com/questions/338456/… $\endgroup$ – safesphere Aug 22 '18 at 4:38

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