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If a composite (pseudo)Goldstone boson $\phi$ emerges in a spontaneous symmetry breaking (similar to the mesons of QCD), is the emission of the $\phi$ particle suppressed in high-energy processes, i.e. in processes with energies $E$ much larger than the symmetry breaking scale $\Lambda$? In other words, can the composite $\phi$ boson carry energies of $E\gg\Lambda$ or does it then "break apart" into its components? For example, if we consider fermion annihilation $\bar{\psi}\psi\rightarrow\phi$ through the coupling $g\bar{\psi}\psi\phi$, would the coupling $g$ be suppressed by $\Lambda/E$ or some higher power?

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