# Electromagnetism Ampere's law Application to solenoid

Electromagnetism;Ampere's Law Application for finding magnetic field strength(B) inside a current carrying solenoid

Question is that why we multiply the current in one loop to the number of turns(enclosed in amperian rectangular loop) ALTHOUGH the current flowing(charges flowing per unit time) is SAME through all the loops??? There is a SINGLE complete circuit If there would be more than one circuits comprising each loop, then i think we should add all currents in individual loops BUT in this situation there is a single circuit... I hope my question is clear

An Amperian loop $abcd$ is shown in the diagram below.
So you perform the integration $\displaystyle \int_{\rm abcda} \vec B \cdot d \vec s$ around the closed loop $abcda. That closed Amperian loop defines a surface (shown in pink) and you need to sum the total current passing through that surface$\vec I_{\rm enclosed}$which you will see is the same magnitude current passing repeatedly through the Amperian surface. That is what Ampere's law demands that you do. You could have the Amperian loop just encircle one wire and that would give the same result for the magnetic field$B$because the path for the line integral would be correspondingly shorter. Source of unmodified diagram. • Sir can you explain what is wrong in taking the amperial loop as a circle of a radius$r$, where$r$is the distance from the axis of solenoid? B should be same due to circular symmetry, but since there would be no current enclosed in that circle (because current flows through the wires on the surface), so that should give$0$magnetic field. – Harry Potter Mar 31 at 10:11 • No. I enclosed equals zero but so does$ \int_{\rm loop} \vec B \cdot d \vec s\$ as the magnetic field is at right angles to the loop. – Farcher Mar 31 at 11:25