Why does it happens, if fixed charges don't oscillate the em field?

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  • $\begingroup$ Perhaps you are interested in a point of view about the interaction without a virtual photon explanation: physics.stackexchange.com/q/415559 $\endgroup$ – HolgerFiedler Jul 29 '18 at 20:10
  • $\begingroup$ @HolgerFiedler Well, there is pinned document as well, I need time to read and understand it, thank You $\endgroup$ – user202676 Jul 30 '18 at 11:37
  • $\begingroup$ @HolgerFiedler And why -2 votes? $\endgroup$ – user202676 Jul 30 '18 at 11:39
  • $\begingroup$ Artur if you click on the points (on a pad or a PC, not on smartphone), you’ll see the plus and minus. At the moment you got +3 and -3. but why you worry about points? You want to learn something here. $\endgroup$ – HolgerFiedler Jul 30 '18 at 17:25
  • $\begingroup$ @HolgerFiedler Хах, I'm about Your answer) Why there -2? $\endgroup$ – user202676 Jul 30 '18 at 17:37

Coulombs law developed from the observation of the interaction of charges, and started as classical physics. Photons are in the realm of quantum mechanics, as they are elementary particles.

Elementary particles obey Coulombs law , but the equations used are quantum mechanical equations, where the coulomb potential is used, between two electrons, for example. In quantum field theory, a calculational tool at the quantum level, the two electrons exchange virtual photons, and that is how the interaction is explained, quantum mechanically.


One should not confuse the classical electricity and magnetism framework of macroscopic interactions with the microcosm where quantum mechanics reigns. Photons belong to quantum mechanics. charges exist in both frames, but different mathematical models describe the data.

  • $\begingroup$ In pre-last sentences, two electrons, You mean two electrons, that don't move relative to each other? $\endgroup$ – user202676 Jul 29 '18 at 18:42
  • $\begingroup$ yes, moving or not as initial condition, the solutions are there, but there will be a repulsion which will lead to motion $\endgroup$ – anna v Jul 29 '18 at 18:43
  • $\begingroup$ Wait a moment, do understand correct - fixed and that move with constant velocity emit a virtual photon, accelerating - emit a real photon? $\endgroup$ – user202676 Jul 29 '18 at 18:45
  • $\begingroup$ I'm actually reading this physics.stackexchange.com/a/68947/202676 Your answer, but it's not easy to understand things, You know $\endgroup$ – user202676 Jul 29 '18 at 18:48
  • $\begingroup$ it will depend on the acceleration if a real photon is emitted. Virtual photons are mathematical entities which allow to do the integrals which will give values to be compared with specific experiments. $\endgroup$ – anna v Jul 29 '18 at 18:53

As i understoot, since the fixed charge are not emitting photon but they have their electric and magnetic fields .the energy is emitted from the charge particle only when particle in motion .since particle is not moving it will have fixed electric and magnetic field and thus there is no disturbance in these field lines ,now since energy is carried by the waves caused by the disturbance in electric and magnetic fields .hence there is no energy traveled .there fore a charge particle can interact with other charge particle without emitting photon(energy)only through the ineraction between their electric and magnetic fields


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