An antimuon and electron may bind together via Coulombic attraction and then decay, but is the following process possible? $$(\mu^++e^-) → \gamma + \gamma$$
$\mu^+$ : antimuon
$\gamma$ : photon
$e^-$ : electron
Which of the following claims are correct?
a) This decay mode can proceed naturally.
b) This decay would violate electron-lepton number. $$0 + 1 (e) \rightarrow 0 + 0$$
c) This decay would violate muon-lepton number. $$-1(\mu^+) + 0 \rightarrow 0 + 0$$
d) This decay would violate tau-lepton number. $$0 + 0 \rightarrow 0 + 0$$
e) This decay would violate charge conservation. $$+1 - 1 \rightarrow 0 + 0$$
The antimuon has a lepton number of -1. The electron has a lepton number of +1. So lepton number isn't violated - that takes out b) c) d).
I thought annihilation had to occur with a particles respective antiparticle. i.e. electron-positron, etc. Meaning a) is also not correct.
Charge of the electron is -1, and antimuon is +1. therefore charge would be conserved - ruling out e)
Of all my assumptions here a) is the only one I'm not too sure about.