# Varignon's theorem (Principle of moments) failure?

"If many coplanar forces are acting on a body, then the algebraic sum of torques of all the forces about a point in the plane of the forces is equal to the torque of their resultant about the same point."

Consider the following case:

Let's consider net moment about the point O.

Algebraic sum of torques gives us √2F*√2a + F*a = 3Fa

But resultant of the two forces = F in downward direction gives us the torque Fa

Clearly Varignon's theorem breaks down in this case. I've read elsewhere that Varignon's thorem doesn't apply for cases where a couple of forces is involved. And that's obvious. Because resultant of couple is 0 force which gives 0 torque - and that is wrong.

But in this case, the two forces don't seem to form a couple. The horizontal component of √2F force does form a couple with the bottom force, but that way, in a generalised problem with n forces, many components can form a couple. So how do we know when not to apply varignon's theorem?

• The forces have to be concurrent (see e.g. Varignon's theorem (mechanics) ). They are not concurrent in your case, so the theorem does not apply. Commented Jul 17, 2018 at 16:53
• @NickD concurrency is a necessary condition. However, I have paraphrased an alternate statement of the theorem from the same wiki link, and this doesn't talk about concurrency. Can you please confirm wiki is wrong? Commented Jul 18, 2018 at 9:18
• I don't know which wiki you quoted (I don't see a link) but the "coplanar" part above should probably read "concurrent". Also your statement about the couple is wrong: the resultant force may be 0 but the torque is not. Commented Jul 18, 2018 at 12:52
• @NickD I'm quoting the wiki link you added in your first comment. You're misreading the 0 torque statement. I'll edit the phrasing so it's clearer Commented Jul 18, 2018 at 14:25
• I checked the reference: the "coplanar" part is a mistake (which I fixed). Commented Jul 18, 2018 at 16:47