Let's say we have 2 inductively coupled circuits with mutual inductance M, and Circuit 1 ist connected to a power source, changing its current by $\frac{dI_1}{dt}$, then the potential induced in Cuircit 2 would be $-M\frac{dI_1}{dt}$, resulting in a current $I_2=-\frac{M}{R_2}\frac{dI_1}{dt}$, thus consuming a power of $-M\frac{dI}{dt}I_2$. My question is: where does this power come from?
I would assume that there would be some resistance/counter-potential in Circuit 1 created by Circuit 2 that would then result in energy conservation. However, I have just learned about energy conservation in a single circuit with self-inductance, and from my understanding we did not take any induced resistance/counter-potential into consideration. Instead, when the current was increasing the induced potential simply reduced the energy output by opposing the direction of the current and thus did negative work. This reduced energy was then "stored" in the magnetic field, which would then be released when the current decreased again, because this time the induced potential is in the direction of the current, hence resulting in no net change of energy.
However, this idea of storing the energy in the magnetic field couldn't work with the 2 coupled circuits, since the induced potential is always in the direction of the current (assuming Circuit 2 has no other energy sources), so regardless of whether current is increasing or decreasing in Circuit 1, positive work is done in Circuit 2.
So how does this actually work? If there is such a thing as induced resistance/counter potential, why do we ingore it in the self inducting circuit, and if there is not such a thing, how is energy conserved for the 2 coupled circuits?