I'm toying with an infrared thermometer - one which you point onto an object, press the button and it instantly measures the temperature by estimating the infrared radiation from the object. It shows more or less the room temperature when I point it to things in the room.

Now I open the window. The temperature outside is 12 degrees Celsius. I point the thermometer to the ground - it shows something near 12 degrees. When I point it horizontally and directed onto a building located several hundred meters away - it shows something like 5 degrees. When I point it onto the sky it shows an error message indicating that the measurement result is below zero Celsius and it can't display it.

This doesn't make sense - the ground has the same temperature as the air and there's a thick layer of air above, so wherever I point the thermometer the temperature is more or less the same and so the infrared radiation intensity should be more or less the same. Yet the thermometer displays largely different results.

Why does the infrared thermometer display much lower temperatures when directed to the outer air compared to when directed onto nearby solid objects?

  • $\begingroup$ You got an explanation in the first paragraph backwards. An infrared thermometer estimates the temperature by measuring the infrared radiation. It is, of course, an estimate, because the thermometer has no way of knowing the emissivity of the object you're pointing it at. $\endgroup$
    – AI0867
    Commented Feb 4, 2021 at 12:32

5 Answers 5


The reason for this can be seen by examining how an infrared thermometer works. As you mentioned, it measures the infrared radiation, and uses this to determine the temperature. So, with that in mind, we consider what happens in the situations you mention. Namely, you cannot use it to measure the air temperature, because the emissivity of the air is piss-poor. So it will "think" the air is very cold, when it is not. Pointing at the sky, well, there's no IR emission of any great significance, that the device would register.

This can be seen by examining footage taken with a thermal infrared camera. This shows how the world "looks" in the thermal infrared band that these devices use. Using such a camera, one sees that the sky appears black. There is little emission, and there is practically no Rayleigh scattering of sunlight either at these wavelengths (it scatters better in the visible spectrum, esp. toward the blue, which is why the sky is blue).

For pointing at a far-off building, the distance means the amount of IR light reaching the device will be too small for it to make a proper reading.

  • $\begingroup$ Regarding the far-off building, the measuring cones of these thermometers are pretty large, so you're probably averaging the building with the ground and a fair chunk of sky. $\endgroup$
    – AI0867
    Commented Feb 4, 2021 at 12:36

The sky at night (no clouds) typically measures -48c to -21c at my location (Seattle), currently -44c. The clouds measure -5c to -1c right now. The trees across the road are at 2c.

The reason I can measure the clouds is that the atmosphere is largely transparent to IR, so my thermometer "sees" the radiation from the clouds, but not the atmosphere - the intervening gasses don't tend to absorb or emit photons of IR radiation, so don't interfere with the measurement (the technical term for this is "piss-poor emissivity").

Water is a good emitter - so if it were raining (and, being Seattle, I'm surprised it's not), it'd mainly "see" the radiation coming from the droplets (although the temperature reading might also be wildly inaccurate, because your typical cheapo IR thermometer doesn't actually measure the dominant IR wavelength - which would allow an accurate calculation via the Wien displacement law - but instead measures the total IR emitted at a specific wavelength, extrapolating that back to a temperature via the Stefan-Boltzmann law, which is that the amount of radiation emitted is proportional to the fourth power of the temperature).

As for the -44c of the clear sky: either something up there (eg ice/dust particles in the stratosphere) is emitting at that ambient temperature, or the temperature reading is meaningless. I tend to prefer the former view, as the temperature is remarkably consistent depending on the season :)

If your thermometer went below 0c, I presume you'd see the same.

  • $\begingroup$ Addendum to the stratosphere: that temperature's going to be wildly inaccurate too, since my thermometer measures total IR, and for the Boltzmann calculation to be accurate the object being measured has to cover your entire field of view (obviously, there's a lot of space between dust particles). $\endgroup$
    – MikeM
    Commented Nov 16, 2015 at 5:01

For completeness, since this came up again:

An infrared thermometer is a thermometer which infers temperature from a portion of the thermal radiation sometimes called blackbody radiation emitted by the object being measured.

To get accurate readings from an infrared thermometer, the emissivity of the body aimed at has to be gauged and applied to it.

By knowing the amount of infrared energy emitted by the object and its emissivity, the object's temperature can often be determined. Infrared thermometers are a subset of devices known as "thermal radiation thermometers".

Emissivity:The ratio of the radiation emitted by the surface at a given temperature to the radiation emitted by a blackbody at the same temperature

Air does not follow a black body radiation curve well and has a very small emissivity, of order of 0.3 for normal humidity and CO2, therefore will be far away from the callibration curve of a given thermometer.

One has to know to what emissivity value the infrared thermometer is calibrated to really have a temperature measurement.



I have read that for object with a very low emissivity will reflect heat from objects.

So if the night sky has a very low emissivity it seems that my thermometer should be reading the reflected ground temperature.

Or is it that objects with low emissivity are transparent?

I'm interested in cooling with the night sky. Rather than air condition an entire wearhouse I want to cool just me. I can buy a vest with phase change wax. It would be cool (pun intended) if I w could cool the wax by radiative cooling into the night sky. The phase change temperature is 55°F.

I want to understand emissivity in this use.




Quote from thr link above

" You can use an infrared thermometer to see the impact of water vapor on warming the atmosphere. The temperature in outer space approaches absolute zero, which is -273 degrees CelsiusA scale for the measurement of temperature named after Anders Celsius, a Swedish astronomer, who invented it. Water freezes at 0 degrees C and boils at 100 degrees Celsius. But you will measure a much warmer temperature if you point an infrared thermometer at the sky directly overhead (the zeniththe point directly above a location on Earth's surface, that is, the up direction" zenith). Depending on the seasonA period of the year that is identifiable by some pattern; in particular differences in weather, ecology, and hours of daylight due to the tilt of the Earth on its axis. These differences create a division of the year. In the mid-latitudes the four seasons are summer, autumn or fall, winter, and spring. In the Tropics, seasons may be identified as wet versus dry season and your location, the temperature will likely be near or below zero degrees Celsius. While this is very chilly, it’s far from being as cold as absolute zero. The difference is caused mainly by water vapor in the sky that has become warm by absorbing infrared radiation emitted by the Earth below. The warmed water vapor returns some of the infrared back to the Earth, and this helps keep the Earth warmer than space. "


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