In reading these discussions I often see these two different definitions assumed. Yet they are very different. Which is correct: Does gravity CAUSE the bending of spacetime, or IS gravity the bending of spacetime? Or do we not know? Or is it just semantics?

Would, in the absence of spacetime, my apple still fall to the earth?

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    In the absence of spacetime, what does "fall" even mean, if there's no space in which to fall? What is the observable difference between gravity "causing" or "being" the bending of spacetime? I'm not convinced this is a well-defined question. – ACuriousMind Jun 26 at 19:52
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    In the absence of spacetime, where would you keep your apple in the first place? – WillO Jun 26 at 19:57
  • Comments are not for extended discussion; this conversation has been moved to chat. – ACuriousMind Jun 28 at 21:15
up vote 87 down vote accepted

I think the correct answer should be that what we call gravity is a fictional force which we experience due to living in an accelerated reference frame (as opposed to an inertial one). Unlike other forces, the force of gravity disappears by a coordinate change. If a person is in a falling elevator, they experience free fall, i.e. they feel like they are floating, and they would conclude there is no force of gravity acting on them. However we at the surface of the Earth would say that clearly the force of gravity is causing the elevator to plunge ever faster towards the ground.

Of course the solution to this odd state of affairs is that gravity is not a force at all. We live in a four dimensional universe with a pseudo-Riemannian geometry in which freely falling objects move along geodesics, or lines of shortest space-time distance. Because the geometry can be intrinsically curved (like the surface of a sphere), those geodesics are not what we think of as straight lines. The person inside the elevator moves along a geodesic, while we on the surface of the Earth are accelerated and do not move along a geodesic. The space-time paths (or worldines) of the elevator and the ground underneath it are not straight lines, and so they intersect at some point. That intersection is the point in space-time at which the elevator hits the ground.

One way to think of this is to consider two ants walking along lines of longitude on a globe. Lines of longitude are great circles, and are geodesics of the sphere. The two ants start at the equator on different lines of longitude both heading due north at the same speed. Their paths are initially parallel to each other, but as they move along the curved surface the distance between them shrinks until they eventually collide at the North Pole. It appears as though there is a force which is pulling them together, but in fact the force is fictitious, the reason they got closer is because on the sphere the geodesics converge and cross each other, unlike in flat space where the geodesics are straight lines which never cross. If the globe is very large, the ants will never know that they are moving on a curved surface, and so would conclude that there must be some force which attracts them. This is the fundamental picture for how "gravity" works from the perspective of General Relativity.

Now to your question, the difference is subtle. While what we refer to as "gravity" is subject to semantics, there is something more profound going on. General Relativity is usually referred to as a "theory of gravity", in which case we can think of the answer as the latter: by definition, gravity is the bending of space-time. On the other hand if we think of gravity as a force, the apparent force of gravity is essentially caused by the fact that space-time is curved. But we can essentially take this logic in circles if we think too much about it, it all depends on what we define "gravity" to be.

But deeper than this is the question of what causes gravity? In classical mechanics we are told that gravity is caused by mass, in the sense that massive bodies have a gravitational field which causes them to attract. But we know that's not the right picture. So to generalize your question, is spacetime curvature caused by mass? In some sense yes, in some sense no. Einstein's equation reads

$$G_{\mu\nu} = \kappa T_{\mu\nu}$$

where $\kappa$ is a constant, the tensor $G_{\mu\nu}$ is a function of the metric, which encodes the curvature of spacetime, and $T_{\mu\nu}$ is the stress-energy tensor which encodes the matter/energy content of the universe.

Because the theory of General Relativity is fundamentally four dimensional, and there is no preferred direction to call "time", we must essentially solve Einstein's equation "all at once". Clearly the matter content of the universe will determine the curvature of the universe, while the curvature of the universe will tell the matter how to move. So you have a sort of chicken and egg problem: matter tells space how to bend and space tells matter how to move.

There is a Hamiltonian (i.e initial value) formalism for GR which works for globally hyperbolic spacetimes (that is, it is not valid for all possible spacetimes). It is called the ADM formalism (named after Arnowitt, Deser, and Misner). It does allow one to set up initial conditions for a spacetime (initial curvature and matter/energy state) and compute the evolution of that spacetime and its matter content over "time" in a way that is generally covariant (does not violate relativity of observers). But this still does not separate the inherent link between space-time curvature and matter/energy content.

As an interesting related question, one could ask whether a massive particle moving through space can interact with itself gravitationally? That is, the mass of the particle distorts space-time and therefore alters its trajectory. There is a similar question at the end of Jackson's "Classical Electrodynamics" regarding accelerating charged particles interacting with their own radiation. I believe his conclusion is that such processes are not really considered because they would create such small corrections. In the context of GR, I would guess such questions fall in the realm of Quantum Gravity.

As to your last question, perhaps you meant "in the absence of space-time curvature". In which case the answer is no, the apple would not fall, all objects would move in straight space-time paths which never intersect and so would always remain at the same distance from each other.

  • A great answer. However there is a similar looping issue with the question about whether the metric comes before or after 4d space (with respect to the comment that there is no preferred direction for 'time'). The metric may pre-define the 3d space + 1d time, which then affects certain of the maths expectations on which much on common explanation is based (e.g. commutivity). Tricky. Likewise from Electrodynamics, 'where is the source of the finite energy' - plane waves are not a solution. – Philip Oakley Jun 28 at 13:23
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    I've removed some "thank you/pat-on-the-back" comments. Please use comments to suggest improvements to the post. – rob Jun 28 at 20:47
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    "Unlike other forces, the force of gravity disappears by a coordinate change". How is gravity different from other forces in this respect? Would an electron "falling" toward a proton be different? – AlexDev Jun 28 at 21:06
  • Yes, because the charge of the gravitational force is inertial mass, so all bodies accelerate at the same rate in a gravitational field. – Kai Jun 28 at 22:13
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    I'm unhappy with the claim that gravity is unlike other forces. You can transform away local gross "acceleration" in any gauge force just like you can in gravity. The only difference is that in spin-1 forces the "acceleration" is a phase shift/rotation in the KK dimensions, instead of a direction in spacetime. The EM 4-vector potential is analogous to the metric tensor. The EM field tensor is analogous to the Riemann tensor: they describe the physical part of the potential/metric tensor that can't be transformed away. – benrg Jun 29 at 6:45

Does gravity CAUSE the bending of spacetime?

What causes the bending of spacetime is the presence of a massive object.

IS gravity the bending of spacetime?


Would, in the absence of spacetime, my apple still fall to the earth?

I do not understand exactly what you mean. However, what I can tell you is that, since the spacetime is curved by the presence of the Earth, the apple will follow the geodesics and therefore it will fall to the Earth.

In addition to P. G. A.'s answer:

Would, in the absence of spacetime, my apple still fall to the earth?

In the absence of spacetime there would be no you, no apple, no fall, no to and no earth. Spacetime is the basic framework in which the universe plays. It is the most basic known fabric of the universe.

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    I don't see how this short, tongue-in-cheek answer the question or help the OP. The OP is asking about the exact semantics and the cause-and-effect relationship of the terms "bending", "spacetime" and "gravity". The example about the apple is very valid. If you know nothing about what spacetime is, it is not obvious that there is no gravity without spacetime. Furthermore, calling "spacetime" a "fabric" is deceiving as well. – AnoE Jun 27 at 10:43
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    It think it answers the part of the question it quotes very well indeed. – T.J. Crowder Jun 27 at 14:57
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    @AnoE "If you know nothing about what spacetime is, it is not obvious that there is no gravity without spacetime." Precisely because I read from the OP's question, that he doesn't quite grasp the meaning of spacetime as the playground of the universe I tried to point it out as clear as I could. I admit that my answer is not so much related to gravity, but spacetime is where all physics as we know it happens, not just gravity. In the absence of spacetime we have the absence of the entire universe. – Javatasse Jun 27 at 18:23
  • @Javatasse, your answer does not even contain the words "gravity", "bending", "cause" etc.; the OP is not asking about whether we can rip spacetime out of the universe, but how everything is related... I fully understand what you are trying to do, I just think it does not work so well as an answer. As T.J. Crowder mentions, you answer one part of the question, which is not the central part IMO. – AnoE Jun 27 at 18:37
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    @AnoE Partial answers are not discouraged and I am making it clear it is just that. The part of the question I answered is about "absence of spacetime" and in that case "gravity", "bending" and "cause" are irrelevant. – Javatasse Jun 27 at 20:00

Gravity doesn't exist. Space time exists and it does not pull.

What you think of as gravity is in fact one of many correction factors that are needed to describe space time to a 3 dimensional Cartesian monkey brain.

Take an analogous example which is slightly simpler.

Remember the militant high school physics teacher who berates anyone who dares utter the words centrifugal force?

The centrifugal force is a correction factor applied when moving from an inertial frame to a rotating frame of reference.

Jimmy appears to be flung to the outside of the car, when it turns. But to the outside observer Jimmy is going straight, whilst the car is turning.

Similarly a planet when viewed locally to the spacetime is going in a straight line when orbiting the sun. For our poor monkey brains we can't imagine a straight closed loop going around the sun. So we ignore the curvature of the spacetime, and imagine a "force" and call it gravity.

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    The worldline of an orbit isn't a closed loop, it's a helix like a very stretched spring. E.g., Earth's orbital speed is about $10^{-4}c$, so the spacetime distance between 2 coils of its helix is about $10000/\pi$ times the spatial diameter of its orbit. – PM 2Ring Jun 27 at 4:59
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    @PM2Ring No. The world line of an orbit is a straight line. Yes, if you want to embed the straight line into a 3,1 SR spacetime, you get a helix plus gravity. If you want to embed the straight line into a 3D Newtonian Space, you get an ellipse plus gravity. Monkey brains use Newtonian mechanics. – Aron Jun 27 at 5:48
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    I'm sure I shall have nightmares about hordes of Cartesian monkeys, with 3-dimensional brains, armed with Killing Vectors. They'll be busy throwing apples out of trees of course. They need to do that, since in their world, gravity doesn't exist. What are the chances one of the apples will hit (and fatally wound) Schroedinger's cat? – Dawood ibn Kareem Jun 27 at 11:51
  • This is interesting. I know very little physics but would like to read more. Can you recommend a good book/site – sudo rm -rf slash Jun 27 at 12:14
  • I read this book recently, and thought it went into the details pretty well… – CrossRoads Jun 27 at 15:15

Once again I feel like all answers are missing a crucial contextual consideration: Gravity as a force is an aspect of a model which allows us to predict events/observations. The curved spacetime of general relativity is another aspect (consequence) of a model which allows us to predict events/observations. Some of the answers write that gravity does not exist, but in the same manner spacetime does not exist. Both are valuable aspects of different models (and thus both do exist as part of those models). The Newtonian model is generally the most useful model we have found so far, but it's inaccurate for certain cases. The "Einsteinian model" is a lot more accurate, but due to its complexity a lot less useful.

Physics can never explain 'why' something happens, it can "only" (very useful, but still "only") create a model which allows us to predict future events. So asking whether gravity causes the bending of spacetime or whether gravity is the bending of spacetime is completely a question of semantics. The highest voted answer by Kai tries to discuss "what causes gravity?" which is a fundamentally meaningless question in physics. The question only gains meaning within a model, at which point the question isn't anymore "what causes gravity", but "how does gravity relate to other aspects of our model?"... which has essentially nothing to do with the real world question of what causes gravity.

So to answer your final question

Would, in the absence of spacetime, my apple still fall to the earth?

Spacetime is no more no less than formulas in a model. They aren't reality, they just model (a simplified) reality. This might sound like meaningless semantics, but what I am trying to communicate is that the question itself is meaningless. General relativity does not work without the spacetime aspect (as it's a natural consequence of it), so in that case the apple would not even exist. Newtonian physics does not have a spacetime (as a single concept), so without it the apple still falls to the ground. And in reality - as far as we know so far (!) - the apple will always fall to the ground regardless of whatever model we humans come up with.

  • yes, we must remember that the apple is real and gravity is real, but spacetime is a model. There is no aether. – foolishmuse Jun 28 at 15:22
  • @foolishmuse Gravity is as real as spacetime is real. That's what I was trying to explain here. Past human observations of the apple moving to the ground are absolutely real. Us creating "the force of gravity" is a model which allows us to predict how the apple is going to move when we drop it in the future. – David Mulder Jun 29 at 9:22

I comment the last question:
Would, in the absence of spacetime, my apple still fall to the earth?

The Einstein's field equations relate the geometry of spacetime to the distribution of mass and energy:
$R_{\mu\nu} -\frac{1}{2} R g_{\mu\nu} = 8 \pi T_{\mu\nu}$
$c = G = 1$ natural units
$R_{\mu\nu}$ Ricci tensor
$R$ Ricci (curvature) scalar
$g_{\mu\nu}$ metric tensor
$T_{\mu\nu}$ energy-momentum tensor

If the R.H.S. is zero everywhere, i.e. no mass or energy, the L.H.S. simply describes a flat spacetime, that is the Minkowski spacetime. The supposition In the absence of spacetime ... is not envisageable, as what shapes spacetime is the mass and energy.

No mass and energy ---> Minkowski spacetime

To answer the question:
1. If no earth: the apple would not fall (no mass to curve spacetime), but would persist in its inertial state of motion.
2. If earth exists: the apple would fall, as the mass of the earth would bend spacetime.

  • Ricci-flat spacetimes must not necessarily be Minkowski. They allow, for example, gravitational wave solutions. (But otherwise the argument is correct). – Sebastian Riese Jun 27 at 21:31
  • @Sebastian Riese. Of course, but here the focus was about spacetime itself. – Michele Grosso Jun 28 at 16:04

protected by Qmechanic Jun 27 at 5:39

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