Connection between theory of superconductivity and Bohmian mechanics I stumbled upon an interesting chapter of Feynman Lectures about Superconductivity and was surprised to see that the equations of motion of the superconducting electron fluid (21.38 and 21.39) hold a term known as Quantum Potential from Bohmian mechanics (the last term in the first equation):
$$
\begin{equation}
\label{Eq:III:21:38}
\left.m\frac{dv}{dt}\right|_{\text{comoving}}\kern{-0.5ex}=
q(E\!+\!v\!\times\!B)\,+\,\nabla{\frac{\hbar^2}{2m^2}
\!\biggl(\!\frac{1}{\sqrt{\rho}}\nabla^2\!\!\sqrt{\rho}\!\biggr)}.
\end{equation}
$$
$$
\nabla \times v=-\frac{q}{m}\,B.
$$
Seeing this I was wondering if Bohmian Mechanics might have been misinterpreted in the past as a theory about a single electron? Maybe it is in fact a theory describing the behaviour of many charged massive bosons (like cooper pairs of electrons in the case of superconductivity), where the wave function becomes a classical observable (as Feynman explains quite nicely)?
 A: It happens quite often in physics that equations from rather different areas have a similar form (A professor I knew, for example, used to say: "Statistical physics is exactly like quantum mechanics without the $i$".) So no, Bohmian mechanics has not been "misinterpreted" just because there is some similarity to other equations in physics. You may want to read up more about Bohmian mechanics for example here to understand its merits describing non-relativistic quantum particles: https://arxiv.org/abs/quant-ph/0408113
I am not an expert on superconductivity, but I can present a strong similarity between the Bohmian law and fluid dynamics:
From the Schrödinger equation, the following continuity equation follows. Here $\rho = |\psi|^2$.
$$ \frac{\partial \rho(x)}{\partial t} = - \nabla \cdot j(x)$$
with the so-called quantum current $j(x) = 2 \Im (\psi^*(x) \nabla \psi(x))$. This type of equation can be found also in the dynamics of fluids, where then $\rho$ is the density of the fluid and $j$ its current. For fluids, this can be expressed as $j = \rho v$, with velocity field $v$. If you take the analogy further, and also read the quantum continuity equation as a similar thing, you get for the velocity:
$$ v(x) = \frac{j(x)}{\rho(x)} = 2 \Im \frac{\psi^*(x) \nabla \psi(x) }{|\psi|^2(x)}. $$
Actually, this is just the guiding law in Bohmian mechanics, which gives the change of the positions $v(Q(t)) = \frac{d}{dt} Q(t)$ of the particles. So you see that a strong analogy holds between the movement of particles in a fluid and the movement of quantum particles guided by a wave function in Bohmian mechanics.
This is also the reasion that experiments like here: https://www.youtube.com/watch?v=WIyTZDHuarQ show the same behaviour as quantum systems to some extent. 
