I have read these questions:
And specifically Anna V's and John Rennie's answers.
John Rennie says when a photon hits a mirror, it is absorbed and re-emitted.
Anna V says it is not absorption and re-emission but it is elastic scattering. She says in her comment to John Rennie's answer:
John, please look at this again, as it is a chosen answer. is not correct for a mirror. Absorption and re-emission would change the phases (the reemitting source would have random direction) and no images would be transmitted to the eye , to call it a mirror. It has to be elastic scattering for a mirror
She says that with absorption and re-emission the problem is, that the re-emitted photon can change direction and energy too, and so the phase of the photon will change too, and that is not a mirror image. Elastic scattering is the one that will keep the energy level of the photon and its phase too.
re-emitted photon can change both direction and energy with respect to the originating one, and the originating one loses energy, i.e. changes frequency. If it is reflected, it of course goes with velocity c (as all photons) whatever its direction (elastic scattering means only change of direction and not energy).
So there can be two cases here:
When a photon hits a mirror, the photon gets absorbed and re-emitted.
There is no absorption and re-emission, but only elastic scattering (Rayleigh).
None of these answers give an explanation to what happens when a photon hits a mirror.
- Which one of the two is it when a photon hits a mirror?