# If you make an effort to escape a black hole, would your free fall velocity be slowing down?

If you make an effort to escape a black hole, would your free fall velocity be slowing down? It is known that you can't escape once you passed event horizon. But is it possible to slow down? Or should I make a sample numbers. The escape velocity where you stand is $1,5 c$, your free fall speed at the moment is $0,75 c$. If the pilot start to begin escape attempt with $0,6 c$ in the normal world, how much is the free fall speed now? Or perhaps instead of slowing down, the free fall become faster now, because it turns out that there is only one direction in the black hole??

• Could you give us some idea of your level of background in physics and math? Your question is ambiguous, because there is more than one way to define velocity here. If you define your velocity as the derivative dr/dt of the Schwarzschild radius with respect to the Schwarzschild time, then $v\rightarrow0$ as you approach the event horizon. – Ben Crowell Jun 14 '18 at 12:01
• Possible duplicate of Why can't you escape a black hole? – sammy gerbil Jun 14 '18 at 12:03
• How is the word effort compatible with the word free fall?? – Qmechanic Jun 14 '18 at 17:39

There is no such thing as an "escape velocity" inside the black hole, because inside the coordinates $r$ and $t$ are interchanged. This means that the flow of time is represented by decreasing $r$. So whatever rocket thrust you have, you can't even hover at $r = const.$