# Above-the-ground pool slope pressure calculation

I'm not sure this is the right place to ask this "homework" question, but I have a real life problem that requires calculation and I do not have the math knowledge to make them myself.

I have bought an above-the-ground pool, with dimensions of 2x4 meters and water level of 1 meter. The image below describes exactly the model I have.

The only place I have to install it has a slope that will result in a 10cm difference in water level. The difference is between the narrow side of the pool. In other words if I will fill the pool with 1 meter water level, on one 2 meter side the water will be 1 meter high and the other side it will be 0.9 meter high.

From my understanding this difference will create more pressure on the wall with the higher water level.

My question is, what water level should I achieve on the higher end so that the pressure on this wall would be as it would have to be if the pool would be on a flat surface with 1 meter water level

Thank you so much for the help.

• Dig the ground out so that the pool is level. – MaxW Jun 12 '18 at 19:13
• 8 m3 of water is 8 tonnes. On a 10cm over 200cm slope, that’s a sideways force of 4000 N trying to roll the pool sideways. Will rise side brackets be able to stably resist that? I agree with @MaxW, you should dig out a flat spot. – Bob Jacobsen Jun 12 '18 at 19:46
• I agree that ideally I should dig to make the pool level. Unfortunately I already made a mistake and filled it with water. So what I'm trying to understand is can I somehow compensate the the pressure by filling less water. After this hot season I would empty the pool anyway and level the ground. – Dimkin Jun 12 '18 at 21:18
• Not clear what you are asking. – sammy gerbil Jun 13 '18 at 18:55

But if you keep the deep-end wall filled to the same $1$ metre depth, there will be exactly the same pressure at each point on the wall, no matter what happens in the rest of the pool.