Every source I can find right now just says something like 'energy/ heat is released by nuclear fission' but I can't find a description of the specific mechanism.

I know that the energy 'conversion' so to speak is from 'nuclear' [in the mother nucleus] to 'thermal' [in the coolant (water)], but I'm looking for an understanding of what's happening on a fundamental level.

I know that the daughter nuclei and free neutrons will have kinetic energy. Is this then transferred to the water via atomic collisions?

Do the gamma rays help to heat the water? If so, how?


When an isotope fissions, it releases somewhere between 2-3 fast neutrons, prompt gamma rays, and usually two fission products. The fission products are radioactive, and some of the fission product decay releases additional energy in the form of beta rays, gamma rays, and neutrinos.

Most of the energy (about 80 percent) is released as kinetic energy of the fission products, which causes the nuclear fuel to heat up. In most commercial reactors, water flows through the core to remove the heat from the fuel, and the water is used to produce steam for a turbine.

There are several different sources for exactly how much energy is released. In the book "Nuclear Reactor Theory", by J. R. Lamarsh (1966), the following table is given:

Fission fragments  168 MeV
Fission product decay
  beta rays          8 MeV
  gamma rays         7 MeV
  neutrinos         12 MeV  (this energy cannot be recovered)
prompt gamma rays    7 MeV
Fission neutrons     5 MeV
Total              207 MeV

More up-to-date data can be found in the ENDF/B data, but it is fairly close to the table shown above.

| cite | improve this answer | |

In nuclear reactors the heat is used (if it is used1) to drive some kind of engine. In large land-based power-plants the heat absorbed by water is used to drive steam turbines.2 Most of these reactors have use water as a moderator, so the working parts of the reactor are under water at all times. In graphite moderated reactors the working fluid (i.e. water) runs through the moderator in pipes and is heated by contact with the hot moderators.

At the microscopic level heat occurs when fast fission fragments or gamma rays hit other molecules and set them in motion.

There is also a class of devices called "radiothermal generators". These use the heat more directly to run electrothermal generators. This is even less efficient, but they have no moving parts and are very compact. They are used on spacecraft.

1 Some small reactors are run purely for training or to make use of the neutron flux. Often called "test reactors" they are not used to generate power at all.

2 For safety reasons the water heated by the reactor is actually run through a heat exchanger to heat a different water supply which is used to run the turbine.

| cite | improve this answer | |
  • $\begingroup$ OK, thanks. My question is how is "heat absorbed by water"? $\endgroup$ – User 17670 Jun 6 '18 at 19:42
  • $\begingroup$ Excellent, "At the microscopic level heat occurs when fast fission or gamma rays fragments hit other molecules and set them in motion." was just what I was looking for. Don't suppose you have a source do you? $\endgroup$ – User 17670 Jun 6 '18 at 19:51
  • 2
    $\begingroup$ The relationship between the motion of microscopic parts of a material and temperature is the subject of "kinetic theory" and is roughly 125 years old. Any general physics text or text of thermal physics will do. The interaction of ionizing radiation and matter is younger—perhaps only 75 years old—but any text on radiation protection, or nuclear/particle physics experimentation will cover it in detail. There is also a chapter on the matter in the particle data book, though it assumes you already know the basics and are just need a reminder on the details. $\endgroup$ – dmckee --- ex-moderator kitten Jun 6 '18 at 19:57
  • $\begingroup$ Yeah, I'm clearly not after a source for kinetic theory itself. I wondered how much of the heating from was the fast fission fragments and how much from the gamma rays (if at all) $\endgroup$ – User 17670 Jun 6 '18 at 20:01
  • 4
    $\begingroup$ @User17670 Actually, the fast fission fragments almost never interact directly with the water (or other heat transfer medium) but stop inside the fuel elements due to collisions with atoms (fuel, fission products, or containment materials which prevent the fuel from entering the water) . This increases the temperature of the fuel element, and hence the surface of the element, probably some metal such as zirconium or stainless steel. The water (or gas) surrounding the fuel element then heats by conduction and radiation because it is at a temperature lower than the fuel element. $\endgroup$ – Bill N Jun 6 '18 at 20:55

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.