6
$\begingroup$

I'm an Australian high school student (Grade 12). We are currently covering superconductors as a topic for our syllabus. Can someone explain (inasmuch as an advanced 18-year-old physics student can understand) why Cooper pairs of electrons (as per the BCS theory) only form in pairs? As I understand it, Cooper pairs form between 2 electrons with opposite spin due to a "phonon exchange", wherein the first electron passing through the metallic lattice induces a distortion of the lattice and hence the creation of a region of higher positive charge density behind it, attracting the second electron with opposite spin (we don't need to know why an opposite spin is required). However, if this second electron also passes through the lattice, and hence creates a region of higher positive charge density behind it, why does it not thence attract another electron and so on? In other words, why do Cooper Pairs form and not Cooper chains? Thanks for your help in advance. *Note: I don't mind what level of understanding your reply requires, I will just try my best to understand more complicated ideas. Thanks

$\endgroup$
  • 1
    $\begingroup$ It is because you can only find cooper pair near the Fermi surface only. The two interacting electrons are just above the fermi surface, all other electrons are below. And non interacting. If you solve the Schrodinger, you will find that they are bound with just below 2* Fermi surface. So the two electrons with momenta k and -k, and opposite spin, floating just below Fermi surface can combine, reducing the total energy. They are floating just above the Fermi surface forever. The lifetime of these quasiparticles increases as they come closer to Fermi surface, and at the surface it is infinity. $\endgroup$ – Árpád Szendrei Jun 5 '18 at 2:34
  • $\begingroup$ Thanks Arpad. Makes sense that the outcome is to reduce the total energy. Where you said "all other electrons are below", why is there only two electrons above the Fermi surface? (or is that just a definition/ I should read the Wikipedia page on Fermi surfaces?) Thanks again for your response. $\endgroup$ – SAS2507 Jun 5 '18 at 3:21
1
$\begingroup$

You probably know about the Pauli principle: you cannot occupy a single quantum state by more than one electron. This is in fact related to their spin which is 1/2.

In superconductivity, two electrons team up to build a Cooper pair. The spin of the cooper pair can be 0 or 1. It therefore behaves rather like a boson than like a fermion. This is a key ingredient to superconductivity because now, the Cooper pairs can occupy the same macroscopic quantum state!

If we now think about what happens when a third electron joins the party, the spin of the composite state is half integer again and they are not allowed to team up in a macroscopic quantum state.

So what about four electrons then? Here the spin can be bosonic again. At the moment I cannot think of a reason why - in principle - there could not be a composite state made out of these four.

But already at the level of 2 electrons, the formation of Cooper pairs by the mechanism you present is a delicate business that only works at very low temperatures. The probability of 4 four electrons meeting at just the right spot with just the right momentum will be much smaller for sure. While at the same time, the energy barrier to destroy this team of 4 and break it into 2 pairs of 2 will be very low.

$\endgroup$
  • $\begingroup$ Thanks for your answer. Am I right to hence read that having a Cooper "Pair" of four electrons is possible but very unlikely then? $\endgroup$ – SAS2507 Jun 6 '18 at 1:10

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.