1
$\begingroup$

Consider an RLC circuit,
$\hspace{200px}$,
and let $V_p$ be the amplitude of voltage from alternating current source,$$ V\left(t\right)~=~V_p \sin{\left(\omega t\right)} \,.$$In addition, let $V_{p,\,\text{resistor}}, V_{p,\,\text{coil}}, V_{p,\,\text{capacitor}}$ be amplitudes of voltage across the resistor, coil, and capacitor, respectively.

Then does$$ V_p = \sqrt{V_{p,\,\text{resistor}}^2+ {\left(V_{p,\,\text{coil}}-V_{p,\,\text{capacitor}} \right)}^2} $$ hold?

$\endgroup$
2
  • $\begingroup$ Is the $p$ ("peak"?) subscript information worth retaining in this context, or could it be dropped for brevity? $\endgroup$
    – Nat
    Commented May 31, 2018 at 22:19
  • $\begingroup$ Nat, the "p" is to make it absolutely clear that the voltages are Peak and not RMS, which is most common in electrical engineering $\endgroup$
    – Albert
    Commented Jun 1, 2018 at 11:12

1 Answer 1

3
$\begingroup$

If the RLC circuit has R, L, and C connected in series and V(t) is the voltage across the complete series, the answer is yes:

$$V_p=\sqrt{V_{R_p}^2+(V_{L_p}-V_{C_p})^2}$$

$\endgroup$
1
  • $\begingroup$ You accidentally squared the left hand side :) $\endgroup$ Commented May 31, 2018 at 22:15

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.