This is a three part question. I have answered two of them.
“A pump is spraying water into the air to form a fountain. The water emerges vertically from a jet of cross-sectional area 2.0*10^-4 m^2 at a rate of 1.0*10^-3 m^3 s^-1”
a) What is the velocity of the water as it emerges from the nozzle?
v=(1.0*10^-3m^3 s^-1)/(2.0*10^-4 m^2)
b) What is the power of the pump?
c)If the power is doubled, how much higher will the water rise (ignore resistance forces)
I am lost with this question. The answer is 0.75m.
Initially, I have worked out the height of the initial pump.
But any calculation I try from here results in an incorrect answer