# What is the formula for the intensity of light, and how are amplitude, frequency and number of photons considered?

One formula for light intensity is$$I = \frac{nfh}{At} \,,$$where:

• $n$ is the number of photons;

• $h$ is Planck's constant;

• $f$ is the frequency;

• $A$ is the incident area;

• $t$ is time.

Another formula describes intensity as a function of magnitude of electric field squared:

$$I\left(t\right) \propto \left|E\left(t\right)\right|^2$$

$$I=\left|S\right|=\frac{\left|E\right|^2}{Z_0}$$

How do I reconcile these two formulas?

EDIT:

thanks!

• We have MathJax running on the site so you can write I = \frac{nfh}{At} between dollar signs to get $I = \frac{nfh}{At}$ (or between double dollar signs for a block equation). And ^ marks up exponents so, you don't even have much to learn to get started. – dmckee May 17 '18 at 0:54
• That said, what do you feel needs reconciling? They are for different understandings for how light works. – dmckee May 17 '18 at 0:58
• – StephenG May 17 '18 at 11:13

## 1 Answer

Classical/Wave Model

An electromagnetic wave is composed of an oscillating electric and magnetic fields, which are orthogonal. Our field equations might be described by $$\mathbf{E}(x,t) = {E_0}\sin\left(kx-\omega t\right)\mathbf{\hat x}$$ and $$\mathbf{B}(x,t) = {B_0}\sin\left(kx-\omega t\right)\mathbf{\hat y}.$$ Here the frequency is given by $f = \frac{2\pi}{\omega}$ and the wavelength by $\lambda = \frac{2\pi}{k}$. The amplitues are given by $E_0$ and $B_0$. These equations form a plane wave which has a total intensity, at any point in time, as given by the Poynting vector $$\mathbf{S} = \frac{1}{\mu_0}\left(\mathbf{E} \times \mathbf{B}\right).$$ The time-average of the Poynting vector turns out to be $$I(t) = \left< \mathbf{S}(t) \right> = \frac{1}{2c\mu_0} E_0^2.$$

This is the equation you mention. There are no photons to be counted in this paradigm, for photons are waves and not particles by classical electrodynamics theory.

Particle/Quantum Model

In the high-energy limit, photons act more like particles than waves.

The intensity is defined as power per unit area, and power is defined as energy per unit time. Thus: $$I = \frac{P}{A} = \frac{E}{\Delta t} \frac{1}{A}.$$ The energy of a photon is $E = hf$, so the total intensity for $n$ photons is $$I = n \cdot \frac{hf}{A\Delta t}.$$ In this model, photons are only counted, and not seen as waves. Thus there is no amplitude to be considered.