In terms of nuclear fusion, why exactly does the coming-together of nucleons result in a net gain of energy (at least until iron)?


The graph of binding energy per nucleon as a function of mass number is:

enter image description here

The graph rises at low A, peaks very near iron (Fe, A=56), and then tapers off at high A. The peak value suggests that the iron nucleus is the most stable nucleus in nature (it is also why nuclear fusion in the cores of stars ends with Fe). The reason the graph rises and tapers off has to do with competing forces in the nucleus. At low values of A, attractive nuclear forces between nucleons dominate over repulsive electrostatic forces between protons. But at high values of A, repulsive electrostatic forces between forces begin to dominate, and these forces tend to break apart the nucleus rather than hold it together.

A very heavy nucleus ,say A=240 has lower binding energy per nucleon compared to that of nucleus with A=120.Thus if a nucleus A=240 breaks into two A=120 nuclei ,nucleons get more tightly bound .This implies energy will be released in this process.

Now consider two lighter nuclei (A<=10) joining to form heavier nucleus.The binding energy per nucleon of the fused heavier nuclei is more than the binding energy per nucleon of the lighter nuclei.This means that the final system is more tightly bound than the initial system.Again energy would be released in such a process of fusion


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.