Is the third law of thermodynamics a non-essential law?

The third law of thermodynamics is sometimes called as impossibility of reaching absolute zero of temperature.

But somehow I think it can be inferred from the second law of thermodynamics that it is impossible to devise a cyclically operating device, the sole effect of which is to absorb energy in the form of heat from a single thermal reservoir and to deliver an equivalent amount of work (The Kelvin–Planck statement).

Let's firstly assume that there exists a reservoir with absolute zero of temperature, then what will happen if there is a Carnot heat engine working between two reservoirs of absolute zero temperature and finite temperature?

You find that the heat engine works with efficiency as high as $\eta=1-\frac{T_c}{T_H}=1$, and transfers zero heat to the low temperature reservoir.

This implies that the heat engine absorbs energy in the form of heat from a single thermal reservoir and delivers an equivalent amount of work, which definitely violates the second law of thermodynamics as mentioned above.

As a result, the assumption made at first is not true that a reservoir with absolute zero of temperature do not exist, and thus it is impossible to reach absolute zero of temperature, as demonstrated by third law of thermodynamics.

So, what is the essentially of the third law of thermodynamics?

And its relation to the second law of thermodynamics?

• I would see the 3rd law as saying that as temperature goes towards zero Kelvin, the system must go to the state with minimum energy. Then for a perfect crystal this means that the entropy goes to zero as well since the ground state is non degenerate. Apr 25, 2018 at 12:24

Carnot's theorem looks in some ways like a stronger statement (because it leads a numeric limit lower than unity on efficiency), but that numeric limit is expressed in terms of the temperatures of reservoirs: $$\eta = 1 - \frac{T_C}{T_H} \;.$$ So it allows a violation of the Kelvin-Plank statement if you have a reservoir with zero thermodynamic temperature.2 (Kelvin and Planck didn't have observations of that case, so the loophole would be something new.)