Why polarization filter do not dim the light completely? In a circle there's infinite amount of degrees (eg. 0 deg, 0.00000000000...1 deg etc.) In a ground school we are thought that there's 360 degrees in a circle.
A landscape behind my window is incoherent light source, so it randomly emits photons with all polarization directions.
When I put a polarizer between landscape and my eye... i can still see the everything. But how is that possible if the polarizer transmits only $1/\infty$  of all photons (since there's infinite amount of directions of polarization)?
Even if we assume that there's just 360 degrees in circle... The landscape behind my window is not 360 times darker when I observe it through filter (eg. polarization glasses).
Why won't polarizer dim the light severely?
 A: A polarizer does not work by transmitting one very specific polarization angle and blocking all other - even only very slightly different - polarizations completely.
Instead a polarizer obeys Malus' law: If the angle between the axis of polarization of the incident light and the polarizer's polarization angle is $\theta$, then the fraction of transmitted intensity to incident intensity is $\cos^2(\theta)$. Or, equivalently speaking in terms of photons, the probability that a photon with definite polarization at such an angle is transmitted and not absorbed is $\cos^2(\theta)$.
The reason for this is that any incident polarization can always be seen as a linear superposition of the polarizer's polarization and the one orthogonal to it. The orthogonal polarization is completely blocked and the parallel polarization is completely transmitted - this is the definition of what a perfect polarizer does. Now, an incident electric field vector $\vec E$ at angle $\theta$ is
$$ \vec E_0 = \cos(\theta) E_{||} + \sin(\theta)E_{\perp}$$
in terms of the field in the parallel direction $E_{||}$ and the field in the orthogonal direction $E_\perp$. After the polarizer, all that is left is $\vec E_1 = \cos(\theta) E_{||}$. Therefore, the ratio of the intensities is
$$ \frac{I_1}{I_0} \propto \frac{(\vec E_1)^2}{(\vec E_0)^2} = \cos^2(\theta),$$
which shows Malus' law.
If the polarization angle of the the incident radiation is uniformly randomly distributed among the possible angles, then the average intensity will be
$$ \frac{1}{2\pi}\int^{2\pi}_0\cos^2(\theta)\mathrm{d}\theta = \frac{1}{2},$$
i.e. "totally unpolarized" photons have, on average, an equal chance to be absorbed by or transmitted through the polarizer.
A: Polarizers don’t just filter photons, they also change the polarization of the photons that make it through. If you send 1000 incoherent photons through a polarizer 500 on average will make it through and all of them will become parallel with the Polarizer. Thats why polarization filters do not dim (coherent) light completely. The closer a photon is polarized parallel with the slit the better chance it will make it through. A photon that is almost perpendicular to the slit can still make it through but has less chance. It will then become polarized as it goes through. 
A: If you use a polarizing filter for ultraviolet light you could see that visible light will be dimmed more as if you use a polarising filter for visible light. The ratio of reflected and absorbed light to the light which is going through the filter depends from the slits width.
If 50% of monochromatic light goes through the filter, this means that for some orientation of the filter the light with the polarisation direction from 0° to 90° and 180° to 270° goes through this filter. Behind the filter all light is polarised in the same direction. From this you can conclude that the lights electric and magnetic field components gets rotated and aligned. 
To prove the last conclusion one has to put two filters behind one another. If one filter has the orientation to the other filter of 90°, no light is going through. But, now place a third filter between the others and orient this filter in the direction of 45°. Will you see light going through? If yes, does this prove that light is rotated by a well designed filter?
