Do the seconds cancel out in this equation leaving seconds instead of seconds squared?

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closed as off-topic by JMac, ZeroTheHero, John Duffield, Jon Custer, sammy gerbil Apr 10 '18 at 6:35

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  • 2
    $\begingroup$ $s^{-2}×s=s^{-1}$ ... $\endgroup$ – Nehal Samee Apr 9 '18 at 12:50
  • 1
    $\begingroup$ Yes they do, as Nehal Sammee has demonstrated. In my opinion it's a good thing to include units when you substitute data into an equation, and to simplify the units at the end, treating them like algebraic symbols. It's a good check on your maths. In the case you've presented, it's re-assuring that the final unit is what it should be: m/s. $\endgroup$ – Philip Wood Apr 9 '18 at 13:23

yes, the second cancel the second square leaving it only second More Explanation: v0 + at = m⁄s + (m/s^2)(s)"the s cancels the square leaving it only s"= m⁄s + m/s For example: 4/2^2 x 2 = 4/4 x 2 =8/4 = 4/2


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