In the Rutherford scattering experiment, does increasing the mass (with constant charge) of the nucleus affect the deflection?

When firing alpha particles head on towards gold nuclei so that they are deflected 180 degrees, the only thing that should affect their deflection is the nuclear charge, the alpha particle's charge, and the initial kinetic energy of the alpha particle, shown by energy = kQq/r where r is the distance of closest approach between the alpha particle and the nucleus.

However, alpha particles not approaching the nucleus directly are deflected at an angle - is this angle related to the size or mass of the nucleus at all? Would two nuclei with equal charges cause equal deflection if one nucleus had twice as many neutrons and so was much larger and heavier?

My textbook states that Rutherford reasoned "the core of the atom must be massive on an atomic scale to deflect alpha particles through large angles", implying the angle of deflection is affected by the mass of the nucleus, however it later states that increasing the number of neutrons in the nucleus would not affect the deflection as the charge is the same.

The usual derivation of the differential scattering cross section makes the assumption that the mass of the target nucleus is much greater than that of the incoming alpha particle. This is saying that the nucleus does not recoil when it interacts with alpha particle. Better still assume that the $\csc^4$ formula derivation is done in the centre of mass frame of the nucleus and alpha.
Since observations are made in the laboratory frame a correction has to be applied to the $\csc^4$ formula and that correction does depend on the mass of the nucleus in relation to the mass of the alpha and so changing the number of neutrons whilst keeping the number of protons the same does change the angle of deflection.