If we have an inflation model with potential $V(\phi) = V_0 e^{-\sqrt{\frac{2}{\lambda}} \frac{\phi}{M_p}}$, where $V_0$ and $\lambda$ are free parameters, does this lead to eternal inflation for $\lambda > 1$?
The slow roll parameter $\epsilon_V(\phi) = \frac{M_p^2}{2} (\frac{V_{'\phi}}{V})^2 = \frac{1}{\lambda}$ appears to be a constant and so for all $\lambda > 1$, $\epsilon_V(\phi) < 1$. This seems to imply that inflation never breaks down.