Ohms law can be sated as V=IR. a. Suppose in an experiment, data is collected of the variation of current with resistance R. Next a plot of R vs I -1 is made. How does one determine the value of V from that graph.
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$\begingroup$ This sounds like a standard practical for finding the emf $\mathcal E$ and internal resistance of a cell $r$ with $\mathcal E = I(r+R) \Rightarrow R= \mathcal E I^{-1} -r$. From the graph of $R$ against $I^{-1}$ the two unknowns can be found. $\endgroup$– FarcherCommented Mar 21, 2018 at 8:18
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One possibility would be to plot different points of (R, 1/I) and then solve for I and then multiply R by I to get V. I don’t believe there is any other way...
