I've been given that there is a spring holding a $.25kg$ mass where $k=10N/m$ and is held at $40cm$ and then let go. I've found that the max velocity is $2.53m/s$ and that when the spring is at $20cm$ the velocity is $2.19m/s$

What I'm having a hard time wrapping my head around is finding the position when the kinetic energy and potential energy are equal.

I keep trying to arrange it like so but end up with two unknowns

$.5(10N/m)(\Delta x)^2 = .5(.25kg)v^2$


closed as off-topic by Qmechanic Mar 21 '18 at 6:17

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better" – Qmechanic
If this question can be reworded to fit the rules in the help center, please edit the question.


You know that energy is always conserved so at the point where $U$ and $K$ are equal a.k.a $$U = K$$, you also know that $$U + K = \text{Total Energy}$$. Now you have two variables two equations and I'll leave the rest for you to solve :D Good Luck! Does this help?


Not the answer you're looking for? Browse other questions tagged or ask your own question.