Consider the following question:
A closed container contains a mixture of Chlorine gas and Argon gas. What is the ratio of the average kinetic energy of a molecule of the two gases?
According to the kinetic theory of gases, the kinetic energy of any molecule, regardless of whether it is monoatomic, diatomic or polyatomic, is given by $\frac{3}{2}k_bT$, where $k_b$ is the Boltzmann Constant. Hence the ratio should be $1:1$. This is also the answer and the explanation provided by my textbook.
However, a diatomic gas has $5$ degrees of freedom ($3$ translational $+ 2$ rotational), and according to the Law of Equipartition of Energy, each degree of freedom contributes an energy of $\frac{1}{2}k_bT$. So, shouldn't the kinetic energy of a diatomic gas like Chlorine actually be $\frac{5}{2}k_bT$, in which case the ratio will be $5:3$?