# In which direction does the friction force due to incline act on a car driving in circles on an inclined speedway?

Suppose that we are observing a car driving around an inclined speedway (in circular motion). For example, imagine the Indianapolis 500 Speedway:

Now, we can assume that the cars are driving around a circle whose center is above the ground level - therefore, the net force acting on the car must work in accordance with the direction of the radius of this circle. These are all (in my opinion) forces acting on the car:

1. The force of gravity acting downwards: one component acting towards the asphalt, the other one acting down the slope.
2. The reaction force normal to the asphalt (opposite to one of the components of the force of gravity)
3. The force of friction due to turning - I am not really sore which direction it actually acts - I would say that this force is radial.
4. The force of friction due to the slope

The fourth force is giving me hard time. I would normally say that this force acts up the slope because it opposes one of the components of the force of gravity - acting down the slope. However, with this assumptions these forces would not add to the desired net force, therefore, there must be something wrong in my assumptions. Could you help me to work it out?