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https://i.sstatic.net/M5OaC.jpghttps://i.sstatic.net/M5OaC.jpg

since the the lever is balanced shouldn't the torques on both sides be equal? if so, how are the torques calculated in this case

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    $\begingroup$ Observe that the pivot point is not in-line with the weights, but sits above. $\endgroup$
    – Hot Licks
    Commented Feb 17, 2018 at 21:27

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It seems that the torques are not equal. The left weight is 7 blocks away from the midpoint and the right one is 8 blocks away, so the torque is not the same, given that the masses are equal. Therefore I'm not sure what you are asking exactly?

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  • $\begingroup$ if the torques aren't equal isn't the lever supposed to keep rotating clockwise? $\endgroup$
    – Eyad
    Commented Feb 17, 2018 at 21:23
  • $\begingroup$ Indeed, it is going to be in the clockwise direction, since the right object is further away from the center of rotation, i.e. torque on that side is bigger and since $\dot{\vec{L}} = \vec{T}$, there is going to be rotation. $\endgroup$ Commented Feb 17, 2018 at 22:16
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Is there a minimum amount of torque needed due to friction? The torque becomes smaller as the angle increases, it would stop if it falls below the threshold.

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