0
$\begingroup$

I am trying to determine the donor/acceptor activation energy for the semiconductor InGaP with the Arrhenius equation. However it contains only one parameter for the activation energy, which turns out to be around $55$meV when fitted on my measurements. Does that mean that this is the activation energy for both donor and acceptor or how can I discern them?

When I make the approximation based on the hydrogen atom I get 2 very different ionization energies:

$E_c - E_d = 8.7$ meV (donor)

$E_v - E_a = 69.5$ meV (acceptor)

(obtained by modifying the hydrogen energy with $\epsilon_{InGaP} = 11.8 \epsilon_0$ instead of $\epsilon_0$, $m_e^*=0.088 m_e$ and $m_h=0.7 m_e$ instead of $m_e$. Data was found in the NSM archive for $T=300$K)

$\endgroup$
1
$\begingroup$

When you have either n-type InGaP or p-type InGaP, you need only one Arrhenius plot for the donor or acceptor activation energy in the temperature range where the freeze-out of the donors or acceptors occurs. You cannot determine both ionization energies in a semiconductor that is either n-ytype or p-type..

$\endgroup$
  • $\begingroup$ thank you for your answer. Does that mean that in my case I can compare the theoretical estimation and the fit parameter, and from that conclude that my InGaP sample is a p-type semiconductor? $\endgroup$ – Jxx Feb 9 '18 at 10:00
  • $\begingroup$ @Julien - Usually, the ionization energy estimate using modified hydrogen atom model gives only a very rough estimate. Maybe you can find also some experimental data on donor/acceptor ionization energies in InGaAs.Even though it is probably p-type, I would be reluctant to use an impurity activation energy to identify the conduction type of a semiconductor. Too many things can happen in a semiconductor.Maybe you can do an independent determination of the conduction type, e.g., the simple hot-point probe test. See e.g., en.wikipedia.org/wiki/Hot-point_probe $\endgroup$ – freecharly Feb 10 '18 at 23:25

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.