I'm having trouble understanding the answer for the following problem:
- The diagram below represents a 10-kilogram object at rest at point A. The object accelerates uniformly from point A to point B in 4 seconds, attaining a maximum speed of 10 meters per second at point B. The object then moves up the incline. The object comes to rest at a vertical height of S (point D) when $\theta$ = $ 30 ^\circ$. If $\theta$ were increased to $ 40 ^\circ$, the object would come to rest at a vertical height at: Less than S, Greater than S, or the Same?*
Given the restraints in the problem, I expected the answer to be less than S, because all conditions, including the velocity, and acceleration of the box stays the same in both problems. However, an increased angle should intuitively lead to a decrease in the vertical position where the box comes to a rest. However, the answer key states otherwise: the height remains the same.