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This question already has an answer here:

Why does the work done on a particle is equal to W=F.dx but not W=x.dF ? Where F is the applied force on the particle

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marked as duplicate by sammy gerbil, Qmechanic Feb 4 '18 at 17:26

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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The required explanation is given below, if you have some doubt in this please revert back !!

The explanation is in the image

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  • $\begingroup$ Sorry but What do you mean by force applied by every dx displacement, and why deltax not x $\endgroup$ – user182794 Feb 4 '18 at 17:28
  • $\begingroup$ I said delta x, because x specifies the position of particle at some time. Whereas delta x tells the change in displacement caused by force acting on it. And Force applied for every dx displacement means, for moving some distance delta x, some force is applied, but if we reduce the delta x to infinitesimally small change in displacement we get dx. So Force applied for every dx displacement to occur. $\endgroup$ – Saurav Hiremath Feb 5 '18 at 17:06

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