I have this question in my book
A bucket weighing 1.2 kg when empty is loaded with 5 kg of sand and then lifted to a height of 10 m at a constant speed. Sand leaks out of a hole in a bucket at a uniform rate. One third of the sand is lost by the end of lifting. Find the work done.
In problems like this, one assumes the use of acceleration to counter gravitational acceleration $9.8 m/s^2$.For example, to compute the work done on the bucket you have
$W=Fd = mad = (1.2kg)(9.8m/s^2)(10m) = 117.6J$
However that should give you a net force of zero and the bucket should not move upward.
A. Why can't we just assume some acceleration value $ a > g$ ? If that's the case (i.e using some acceleration value greater than g) does that mean that the actual work done on the bucket neglecting other non conservative forces, is some $W > 117.6J$ because the actual acceleration is again greater than $g$?
B. How is it possible to have a constant speed (as stated in the problem) when lifting when you have a positive acceleration?