-2
$\begingroup$

An electron in a hydrogen atom at an instant $t=0$ have the following wave function: $$\Psi(r,\theta,\phi,t=0)=\frac{1}{2}R_{1,0}(r)Y_0^0(\theta,\phi)+\frac{i}{\sqrt{2}}R_{2,1}(r)Y_1^0(\theta,\phi)+\frac{1}{2}R_{3,2}(r)Y_2^1(\theta,\phi)$$

Is $\Psi(r,\theta,\phi)$ an stationary state? Why?

It will stationary just because does not depend on time, or will be necesary another condition?

$\endgroup$

closed as off-topic by Kyle Kanos, garyp, dmckee Jan 14 '18 at 18:10

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "Homework-like questions should ask about a specific physics concept and show some effort to work through the problem. We want our questions to be useful to the broader community, and to future users. See our meta site for more guidance on how to edit your question to make it better" – Kyle Kanos, dmckee
If this question can be reworded to fit the rules in the help center, please edit the question.

  • 2
    $\begingroup$ Homework assignent? Start reading the book. $\endgroup$ – Pieter Jan 14 '18 at 17:26
  • $\begingroup$ I'm voting to close this question as off-topic because there is no evidence of prior effort or research. $\endgroup$ – garyp Jan 14 '18 at 17:55
0
$\begingroup$

Get the wave function at arbitrary time t. Then calculate Magnitude of w.f by multiplying by its cc. If it does not depend on time it is a stationary state.

$\endgroup$
  • $\begingroup$ This is true as far as it goes and is a working procedure; but there is a much easier way to answer the question (and it sets you up for thinking of quantum mechanics in terms of abstract states and eigenvalues which is advantageous when moving on from the Schrödinger picture). $\endgroup$ – dmckee Jan 14 '18 at 18:14

Not the answer you're looking for? Browse other questions tagged or ask your own question.