An electron in a hydrogen atom at an instant $t=0$ have the following wave function: $$\Psi(r,\theta,\phi,t=0)=\frac{1}{2}R_{1,0}(r)Y_0^0(\theta,\phi)+\frac{i}{\sqrt{2}}R_{2,1}(r)Y_1^0(\theta,\phi)+\frac{1}{2}R_{3,2}(r)Y_2^1(\theta,\phi)$$

Is $\Psi(r,\theta,\phi)$ an stationary state? Why?

It will stationary just because does not depend on time, or will be necesary another condition?


closed as off-topic by Kyle Kanos, garyp, dmckee Jan 14 '18 at 18:10

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  • 2
    $\begingroup$ Homework assignent? Start reading the book. $\endgroup$ – Pieter Jan 14 '18 at 17:26
  • $\begingroup$ I'm voting to close this question as off-topic because there is no evidence of prior effort or research. $\endgroup$ – garyp Jan 14 '18 at 17:55

Get the wave function at arbitrary time t. Then calculate Magnitude of w.f by multiplying by its cc. If it does not depend on time it is a stationary state.

  • $\begingroup$ This is true as far as it goes and is a working procedure; but there is a much easier way to answer the question (and it sets you up for thinking of quantum mechanics in terms of abstract states and eigenvalues which is advantageous when moving on from the Schrödinger picture). $\endgroup$ – dmckee Jan 14 '18 at 18:14

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