# Equipotential Lines in Circuit Analysis

I found this while studying about the symmetry method of determining equivalent resistance. But, I cannot understand on what basis they are coming into this conclusion; how they are calling these points equipotential:

A little bit elaboration on equipotential lines and symmetry method of Circuit Analysis will be very helpful.

• It is symmetrical so any current will split nicely between the 2 paths; i.e. current at A will split equally to B and C. Commented Jan 2, 2018 at 14:19
• @XcoderX actually, my concept about equipotential lines and points is not clear. Can you please elaborate a little please? And how is the line of symmetry and equipotential points related? Commented Jan 2, 2018 at 14:23
• Hmm... basically the line of symmetry tells you that resistance on both sides are equal. Since current splits inversely to the ratio, but here, the ratio is 1:1, so current splits 1:1. This means that the same amount of current goes to both sides, so they are equipotential. My explanation here probably doesn't sound very "sciency", but I hope it is understandable. Commented Jan 2, 2018 at 14:26
• @XcoderX Thanks, my concept is getting clear. I think some more problem solving would give me a proper hold on the topic. Commented Jan 2, 2018 at 14:28
• Perhaps you could upvote and check if it helps. Commented Jan 2, 2018 at 14:30