# Which is the physical meaning of the evanescent wave?

I was reading that for an incident angle greater than the critical angle, there will be a total internal reflection. The cosine of the refraction angle is therefore an imaginary number. If we make a straight forward derivation we get an exponential attenuation factor for the refracted wave. And this wave (named Evanescent wave) only propagates along the boundary. When we replace the cosine of the refraction angle on the Fresnel's formula, the amplitude of the reflected wave is the same of the incident wave, i.e the real part of Fresnel's reflection coefficient is equal to the unity. More calculations gives that there is no flow energy across the boundary and I guess this is why the total amplitude is reflected backward, i.e without losing energy. My questions are here: What is the physical meaning of the evanescent wave? If there are no flow energy why is there a propagation factor (along the boundary) for this wave? If this wave is not propagating how we can understand the existence of this wave? If there is no flow energy across the boundary but there is energy, why is the amplitude of reflected wave the same of the incident wave? is there no loss of energy?

thanks a lot.

• I was doing atr spectroscopy thus I do assume there is energy flow through the boundary between the element in which tir occurs and the sample, by means of the penetration depth of the evanescent wave. Dec 26 '17 at 19:06
• Dec 26 '17 at 22:44
• Possible duplicate of Difference between propagating and evanescent waves Dec 26 '17 at 22:46
• An incident wave excites the medium and the latter raidates in both directions, i.e., reflected wave and refracted wave. The refracted wave interferes with the penetrated (original incident) wave and decays progressively while going inside the medium. The resulting interference picture is known as an evanescent wave. If you put some admixtures in the medium, they may scatter the waves and we can see the evanescent wave inside. May 31 '18 at 11:02