I'm interested in the manufacturing of violins.

I was wondering what the role of the sounding box?

Why would it be worse if there were just a sound board?

Does the box just have to redirect the wave to the top of the instrument? So, it would also work with a box out of concrete (but I think it wouldn't).

Why does the box also have to vibrate, but not just the board and the air inside the box?

Thank you !


2 Answers 2


The sound box couples the vibration of the instrument to the air around it, so that it makes more noise that a vibrating string would alone. The string alone displaces very little air, and so makes very little sound. The much larger surface area of the body means that it can displace much more air, and thus make much more sound when it vibrates.

The material the body is made out of is very important, as it must be light and thin enough to vibrate well, but also strong enough to not give out under the tension of the strings.

You can see essentially this effect by considering an acoustic violin (which has a sound box) to an electric violin (which does not). An electric violin has a solid body, which does not vibrate much and so does not produce much sound, and so requires external amplification.

  • $\begingroup$ So, the role of the box is actually not so different from the board? $\endgroup$ Dec 21, 2017 at 10:13
  • $\begingroup$ And what is the role of the air inside? $\endgroup$ Dec 21, 2017 at 10:13
  • $\begingroup$ @JonasDaverio It's not so much different, just more of the same. The bigger the surface area in contact with air, the more air it can displace. $\endgroup$
    – Chris
    Dec 21, 2017 at 10:36
  • $\begingroup$ Ok. And what would be the effet of an infinitly rigid box over no box at all? None? $\endgroup$ Dec 21, 2017 at 15:05
  • $\begingroup$ Increasing the stiffness (rigidity), $\kappa$, of the box increases the resonant frequency. Eventually the resonant frequency of the string is not well-matched to the body, and the efficiency of the energy transfer is reduced. If you can't transfer the energy of the string to the body, having a large surface area is all for naught. $\endgroup$ Dec 22, 2017 at 21:01

Though it's true that the larger surface area improves the efficiency of the transfer of acoustical energy from the string to the air, there's another good reason for why a violin has the form of a box instead of a board.

The box and it's sound holes behave as a Helmholtz Resonator. This means that unlike a board, the box has a narrowband resonance frequency.

A page devoted to violins on the same website provides an empirical spectrum for the violin, which shows that it has a strong resonant frequency near 300 Hz. The author of the webpage explains the plot like this:

This is the ratio of the sound pressure produced (recorded by a microphone near the f hole) to force applied (electromagnetically at the bridge).

violin acoustic efficiency

So we can see that because of the body design of the instrument, notes near 300 Hz need much less physical force to radiate the same amount of acoustical energy. It should be no surprise that the design of the body matches the range of the instrument: 300 Hz is in the center of the first two octaves of the violin's range (G3 to G5.)

  • $\begingroup$ In that regard, it is not so important for the box to be in wood or particularly thin, is it? Since Helmholtz doesn't depend on the box walls vibrating but only on the air inside it. But you said the box also with the increased area, so it's not contradicting. $\endgroup$ May 4 at 0:02
  • $\begingroup$ I'm wondering if we could imagine a rigid box with a wooden top (playing the role of a soundboard), that would have the same frequency response as a normal violin. Maybe a bigger sound board with roughly the same area as the box of a normal violin, on top of a concrete box with the same Helmholtz caracteristic as a violin. Would it work according to you? $\endgroup$ May 4 at 0:02

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