Would the field in a cavity inside an arbitrary conductor with some charge, which is NOT SYMMETRIC be zero?

My book only says that field inside a cavity is always zero when there is no charge in cavity. But they prove this by taking a sphere with a symmetrical cavity and using Gauss law. But how can I prove this in cases where I can't take $E$ (field) out of:

$$\oint\pmb{E}\cdot d\pmb{A}=\frac{Q_{enclosed}}{\varepsilon_0}.$$

  • $\begingroup$ Note that no charge within the volume enclosed by the Gaussian surface doesn't imply zero electric field within but, rather, that no electric field lines begin or end within. $\endgroup$ Dec 13, 2017 at 12:51
  • $\begingroup$ So the field inside a cavity is not always zero? $\endgroup$
    – ymuf
    Dec 13, 2017 at 14:25
  • 1
    $\begingroup$ The field inside the cavity (assume no charge present) is zero. My point is different, it's that Gauss' law doesn't fix the electric field within to be zero when the flux integral is zero. If there were a non-zero electric field within the cavity, the flux integral would be still be zero as long as there is no charge within, i.e., as long as no electric field lines begin or end within the cavity. $\endgroup$ Dec 13, 2017 at 17:13

3 Answers 3


In a static situation, there can be no field inside a conductor. If there were, charges would move until there was no field. This means that every point within a conductor (including points on the surface of an empty cavity) is at the same potential. This in tern means there can be no field inside the cavity.


The electric field lines from the charge(s) inside the cavity connect to the induced surface charges, in a similar way the outer surface charges of the conductor radiate and terminate at some other faraway charge. There is no reason why they should not. Recall that electric field is only necessarily zero in the non-surface 'flesh' of a conductor.

To utilize Gauss' law, let the Gaussian surface be the same shape as the asymmetric cavity, differing only in size, so that the surfaces are parallel everywhere. Symmetry would be convenient when dealing with numbers and variables, but for a yes/no question it is not necessary.

Enclose the charge(s) inside the cavity while excluding the cavity wall, and you would catch some electric field lines. Electric field in a cavity is not zero when there is a charge inside, regardless of cavity and conductor shape. :3

Edit: To answer a charged conductor of empty cavity. In the cavity, there is no charge for electric field lines to terminate at. By the same principle above, you would not catch any electric field lines in the cavity-shaped Gaussian surface. Edit2: An electric field would not cut through the cavity, because the charges on the cavity wall are the same sign (in other terms, will violate curl(E) if an electric field line were to join in such a way). So there cannot be an electric field inside an empty cavity, generally. C:

  • $\begingroup$ I'm asking about when the conductor is charged and there is no charge inside the cavity. Then will the field inside the cavity always be zero? $\endgroup$
    – ymuf
    Dec 13, 2017 at 15:12
  • $\begingroup$ " there is no charge for electric field lines to terminate at" what's the need for a charge, can't the field lines just pass through the cavity giving a field there? $\endgroup$
    – ymuf
    Dec 13, 2017 at 15:17
  • $\begingroup$ What about a distribution of +q and -q charge on the inner surface of cavity? They can act as source and sink of electrostatic field. $\endgroup$ Apr 1, 2021 at 13:47

Operationally, the way you detect an electric field is to introduce a test charge and measure the force on it.

If there is no test charge in the cavity then you cannot measure an electric field there. It doesn't matter what the field might be.

We can make a handwaving argument that it must be zero, as follows. Imagine the conductive surface is given a strong negative charge. The electrons will space themselves out to create the smallest repulsion for each of them, because it is a conductor and they can do that. Imagine that when they are spaced that way then they exert a force on a tiny test charge inside the cavity. If they do that, then they are not ideally balanced among themselves either, and they will rearrange themselves. So they must be arranged so they would not create that force.

I asserted that they can't make the test charge move without making each other move on the surface. That's plausible but not proven, which is what makes this a handwaving argument.

Notice there could still be an electric potential. Imagine a single electron inside the cavity, while the conductive surface is covered with quadrillions of spare elections. They all push on the inside electron, but the push is the same in all directions. That is not the same thing as being in a cavity with nothing pushing at it. Most ways it's the same. It isn't getting pushed anywhere.

But just as an atom at the center of the earth has no gravity but a lot of pressure....

If the electron with no electrical force on it happened to accidentally touch the conductive wall, then it would immediately move to the outside edge of the wall and jostle a place there for itself. While if there were no charges there, it would presumably continue to move randomly.

Imagine that an insulated wire travels through a tiny hole in the wall. The wire is itself uncharged, but it has a bare end in side the cavity. The free electron will be attracted to that wire, and will leave through it. (Or another will leave in its place.) Without the charge on the conducting surface, that attraction would not be there and the charge would be more likely to be absorbed by the sall than the small wire end. The potential is like a pressure.


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