Is Heisenberg's Uncertainty Principle applicable to light? Can we apply the Uncertainty Principle to light? If so wouldn't it violate it because we just need to find the position of light, since we would already determine it's momentum(from the wavelength of light used)?
 A: No, it is not at least in the usual form (3D momentum-position inequality), because differently from massive particles there is no position operator for photons as is known from the theory of representations of Poincare' group and imprimitivity theory.  See for instance Barut-Racza's textbook on representation theory.
Extending the formalism some interesting results exist like  this one. I do not know if this proposed re-formulation of HUP corresponds to experimental facts. 
I do not think that Fourier analysis is enough, "without introducing $\hbar$", i.e., without quantum phenomenology, to say that HUP takes place for classical systems like waves of sound.
Yes, one could argue that if the Fourier transform of a wavepacket of sound  has extension $\Delta k_1 \Delta k_2 \Delta k_3$, then the spatial extension satisfies $\Delta X_i \geq \frac{1}{4\pi \Delta k_i}$. 
The point is that this spatial extension has not the meaning of the statistical uncertainty of the position of a "particle of sound" because no localization phenomena exist and also because momentum is not related to wave number vector through quantum relation $P= \hbar k$. 
Instead, if we are dealing with a Schroedinger wave of a massive particle  and we perform a sufficiently precise (3D) position measurement, the particle localizes inside the support of the packet. In other words, a relatively small spot of space (also very very small with respect to the extension of the wave) is abruptly and discontinuously chosen by the system.
However, repeating the position measurement for identical waves, the position where the particle localizes fluctuates with a dispersion satisfying $\Delta X_i \geq \frac{1}{4\pi \Delta k_i}$, i.e.,  $\Delta X_i \Delta P_i\geq \frac{\hbar}{2}$.
These phenomenological facts are completely absent for classical waves, because they do not describe quantum particles.
Regarding photons the situation is quite complicated. As far as I know they localize on screens their wavefunction encounters during its evolution. But this is not a three-dimensional localization and it is difficult to handle this phenomenon with the standard Fourier analysis machinery (though we know that the three components of the momentum are related with the wave vector components according to the standard quantum relation $P_i = \hbar k_i$). The mathematical counterpart of this fact is the absence of the standard position operators along the three spatial direction. 
So it is difficult to state a precise form of HUP for photons.
A: Using wavelength you can find only the magnitude of momentum $\sqrt{P_x^2 + P_y^2 + P_z^2}$. For finding its direction you will need its wavevector $\vec{k}$.  Heisenberg's Uncertainty principle applies to each component of momentum and the corresponding component of position, for example, you can't find simultaneously $P_x$ and $x$. Heisenberg's Uncertainty Principle in vector form: $\Delta\vec{P}.\Delta\vec{r} =3\frac{h}{4\pi} $
There is a nice demonstration of this in an experiment of diffraction of light through single slit in this video by Veritasium: https://www.youtube.com/watch?v=a8FTr2qMutA&t=4s
In the experiment, when the light is allowed to pass through a thin slit, it's position is being confined to the slit. So as the slit becomes smaller and smaller it's position gets confined to a smaller region of space. Now, Heisenberg's principle has to work, so its momentum spreads out in different directions (which is uncertainty), giving us the pattern of diffraction.
A: The Heisenberg Uncertainty principle, HUP, is a basic quantum mechanical observation, modeled by the commutation relations of the appropriate operators.
Light is the name of classical electromagnetic radiation, described by Maxwell's equations. It can be mathematically shown that light, (classical electromagnetic waves,) is emergent from an enormous number of  photons of energy h*nu where h is the Planck constant and nu the frequency of the classical EM wave.
The HUP is only relevant for elementary particles and their composites, like atoms and molecules. Photons as individual elementary particles obey the Heisenberg uncertainty principle when their momentum and position is detected . If the interaction point of a photon in space is detected with great accuracy, its momentum will have an uncertainty bounded by the HUP.
I searched for experiments checking the HUP for single photon momentum and position, but I suspect that the experimental errors in position and frequency measurement are so large that the HUP is always obeyed.
The linked video given by Yaman Sanghavi does show the correlation  collectively for  photons building up light, showing that for a fixed momentum/frequency the beam has to spread out going through a narrower and narrower slit, but does not test the bounds of HUP.
Thys the question in the title :

Is Heisenberg's Uncertainty Principle applicable to light?

is answered with "yes" for for the photons uilding up light and other sets of non commuting variables.
This study checks a HUP relationship of photons for non commuting polarizations states and validates the principle.
