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Hawking radiation tells that antiparticles near a black hole are responsible for its reduction.

But I am having doubt, because when one of the particles goes into the black hole, the other particle goes away from it. So this should increase the size of black hole not decrease it, as it has taken something in. And if by chance the negative particle goes into the black hole, the other particle should also go into it, because of its huge pull, so that the black hole size is conserved.

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  • $\begingroup$ 1) What do you mean by negative particle? 2) What is your question? $\endgroup$ – Andrei Geanta Nov 27 '17 at 20:49
  • $\begingroup$ Two particles which are of opposite nature are generated. $\endgroup$ – The immortal Nov 27 '17 at 20:50
  • $\begingroup$ One is negative and my questions are everything i have written after doubt $\endgroup$ – The immortal Nov 27 '17 at 20:53
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The key point here is that the definitions of "zero energy" are different near and far from the black hole. When the virtual particle pair is created near the black hole, it has zero energy, relative to the region near the horizon. Then, a particle with positive mass escapes to infinity. At infinity, however, there is a symmetry that guarantees overall conservation of energy. This means that the black hole had to have lost an amount of energy equal to the energy of the escaped particle. This therefore means that the infalling particle must have had negative mass relative to infinity.

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  • $\begingroup$ +1 for an answer that means my superficial assumptions will have to be reassessed. Also, how come I never see that explanation on the discovery channel :) $\endgroup$ – user176049 Nov 27 '17 at 22:11
  • $\begingroup$ @Countto10: this is still a pretty handwavey argume that I expect someone to be unhappy with, but i did want to make it comprehensible, too. $\endgroup$ – Jerry Schirmer Nov 28 '17 at 15:52

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