I'm working through J. Annet book: Superconductivity, Superfluids and Condensates.

In chapter 6 (BCS theory) the effective Hamiltonian in quadratic form is introduced:

$$\sum_{k\sigma} (\epsilon_k - \mu)c^{+}_{k\sigma}c_{k\sigma} - \sum_{k} (\Delta^{*} c_{-k\downarrow} c_{k\uparrow} + \Delta c^{+}_{k\uparrow} c^{+}_{-k\downarrow} ) \\$$

and then rewritten in a matrix form:

$$ \sum_k{ \begin{pmatrix} c^{+}_{k\uparrow} & c_{-k\downarrow} \end{pmatrix} \begin{pmatrix} \epsilon_k - \mu & -\Delta \\ -\Delta^{*} & -(\epsilon_k - \mu) \end{pmatrix} \begin{pmatrix} c_{k\uparrow} \\ c^{+}_{-k\downarrow} \end{pmatrix}} $$

If I now start with the matrix form, multiply it out, collect terms and compare with the first one I see that I require:

$$ c^{+}_{-k\downarrow}c_{-k\downarrow} = c^{+}_{k\downarrow}c_{k\downarrow} $$

I can't see why this is the case. Have I done something wrong or am I missing something?

  • 2
    $\begingroup$ This is not the case. You must use $\sum_k \epsilon_k c^\dagger_{-k}c_{-k}=\sum_k \epsilon_k c^\dagger_{k}c_{k}$ by changing the dummy variable $k\to -k$, and using $ \epsilon_{-k}= \epsilon_k$. $\endgroup$
    – Adam
    Commented Nov 13, 2017 at 15:42


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