# Why does heat transfer faster when two or more modes are used?

When two metals at different temperatures are allowed to attain equilibrium in vacuum through radiation, theoretically they should attain it faster as compared to when the same metals at different temperatures are in vacuum connected by a metal rod. This reasoning is obvious because the same amount of heat is being transferred. In the first case all the heat travel at speed of light but in the second case some of heat travel at c while the rest travel very very slowly (through metal rod). Even though in the second case the two process occur simultaneously it should take more time because compared to speed of light conduction is an extremely slow process. So we cannot say it with certainty that two modes of heat transfer are better than one Or can we?

• We already measure heat transfer in terms of time for these situations. It's not really clear what you're trying to get at here, with radiation somehow being "faster". – JMac Nov 12 '17 at 16:33
• Radiation being faster means heat transfer occurs fastest through radiation (infrared) – quantised Nov 12 '17 at 16:50
• ...How are you measuring your heat transfer though? Generally you would be measuring heat transfer in terms of watts or watts per unit area. Both of those measure energy per unit time. The "fastest" mechanism depends entirely on the situation. – JMac Nov 12 '17 at 16:58
• I only estimated. "The "fastest" mechanism depends entirely on the situation" how so? – quantised Nov 12 '17 at 17:16
• Most heat transfer equations are based on $Q$ (or $q$), generally measured in $W$ or $\frac {W}{m^2}$. Both of those measure energy per time. If the same amount of heat is being transferred, then there's no overall speed difference between either method, because the change in energy over an amount of time is the same for both. – JMac Nov 12 '17 at 17:20

Technically, your metals do radiate thermal energy at the speed of light (in a vacuum), but that doesn't mean that they transfer thermal energy rapidly.

If you shipped something by a Ferrari (compared to a truck), you'll move it faster with a Ferrari, but you'll move a lot more with the truck.

Radiation is actually a relatively slow way for objects to lose heat and is only significant for very hot objects.

The rate of transfer of heat for objects in a vacuum is

Q ∝ εδT⁴*


where ε is the emissivity (which is very small for metals because they are shiny (0.04 for copper)), δ is a very small constant (5.670367(13)×10−8 W⋅m−2⋅K−4) and T is the absolute temperature. You can see that the Q value for heat flux will be very small.

The absorption of heat is, for the same reason, very slow for metals.

Now consider conduction:

Q ∝ k∆T*


where k is the thermal conductivity (401 W⋅m−1⋅K−1 for copper) and ∆T is the difference in temperature.

The two metals will almost certainly achieve equilibrium much faster with a metal rod between them not only because conduction is much faster and much more effective but also because the metal rod does not hinder radiation significantly.

*Surface area and distance left out because there's not enough info and because they doesn't affect the conclusions.