# What happens to your weight when you go a specific height above the surface of the earth?

How would you use the Universal Gravitation equation $F=\frac{Gm_1m_2}{r^2}$ to calculate the weight of a person at a specific height above the earth?

If, for example, you were 6370m above the earth and you weighed 70kg, would it be as simple as doing $F=\frac{(6.67x10^-11)(5.98x10^24)(70)}{6370^2}$?

The question is asking me whether or not a persons weight goes down by a factor of 4, a factor of 2, stays the same, or goes up by a factor of 2 or a factor of 4. My initial train of thought would be that it doesn't change at all.

As you might be able to tell, I am very new to physics and am struggling to grasp this concept.

Thanks for taking the time to help me out.

• In the formula, r is measured from the center of mass of the Earth to the center of mass of the person... Nov 9 '17 at 2:34
• Nov 9 '17 at 4:52