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I have found that it is possible to calculate the conductivity of a semiconductor using the Boltzmann distribution:

The source is a slideshow presentation and doesn't list much information. The derivation given is as follows: For an intrinsic semidconductor: $\sigma=n|e|\mu_e+p|e|\mu_h$

$\sigma \approx C_1n=C_1p =$

$\sigma \approx Ce^{-\frac{E_g}{2k_bT}}$ where C is a constant and $E_g$ the bandgap energy.

My question is: Where does the half in the exponent of the boltmann distibution come from?

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    $\begingroup$ "I have found that..." - Perhaps it would be a good idea to link the source. $\endgroup$ – Andrei Geanta Nov 5 '17 at 15:58
  • $\begingroup$ From SRH theory assuming a mid-gap state for carrier generation/recombination. $\endgroup$ – Jon Custer Nov 5 '17 at 16:15
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It's hard to say without seeing more of what you did, but if the trap state is halfway between the conduction and valence bands, then it would have energy $E_t = \frac{E_g}{2}$. The equilibrium fraction of the charge carriers in the trap state would then be given by $$ n_t \propto e^{-\frac{E_t}{k_B T}} = e^{-\frac{E_g}{2k_B T}}$$


I think I somewhat misunderstood the question. In intrinsic semiconductors, the carrier concentration goes like

$$ n_i \propto e^{-\frac{E_g - E_f}{k_B T}}$$ where $E_f$ is the Fermi energy. In many semiconductors, $E_f$ is precisely in the middle of the band gap, so $E_g-E_f=E_g/2$.

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  • $\begingroup$ So if I understand it correctly, the formula is based on trap-assisted generation/recombination. In this model the energy needed to generate a hole- electron pair is half of the bandgap energy, and that is why we fill in half of the bandgap energy in the boltzmann distribution. $\endgroup$ – Zephron Nov 5 '17 at 17:02
  • $\begingroup$ @Zephron - correct. See Shockley-Reid-Hall. No mid-gap states and the density of carriers is much lower. $\endgroup$ – Jon Custer Nov 5 '17 at 17:35
  • $\begingroup$ @Zephron I think I slightly misunderstood your question - my answer has been edited. $\endgroup$ – J. Murray Nov 5 '17 at 17:45

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