What does the Kretschmann scalar really tell us about the geometry of spacetime? [duplicate]

The Kretschmann scalar is one of the measures of spacetime curvature. For flat (Minkowski) spacetime it is zero. The dimensions of the Kretschmann scalar are $[L]^{-4}$. What does that physically signify about the geometry of spacetime?

marked as duplicate by Kyle Kanos, stafusa, Jon Custer, David Z♦Oct 27 '17 at 20:00

$$F_\text{tidal} \propto \sqrt{\frac{48M^2}{r^6}} \propto \frac{1}{r^3}$$