# Is this an appropriate explanation of why exactly elastic potential energy is quadratic?

We have a science project about elastic potential energy, and the graph is quadratic. We have to explain why the graph is quadratic without only using the equation as a reference point. Is this an appropriate explanation?

This is because the elastic force is not constant, it increases with extension. When force is pulled equally as hard at all positions, then there is squared the energy to be stored for double the pull-back distance, since this force will pull equally but travel twice as far.

This is because the elastic force is not constant, it increases with extension.

That is correct

When force is pulled equally as hard at all positions,

It can't - you have to use more force as you displace further - that's the point of your first line

then there is squared the energy to be stored for double the pull-back distance, since this force will pull equally but travel twice as far.

The point is that the force is twice as big but travels the same distance, not the other way around.

Of course the work done for increasing the distance is the displacement $\Delta x$ times the force $F$, indicated by the green shaded band. And as you keep displacing, you keep adding more bands. The total area of the triangle is of course the base ($x$) times the height $kx$ divided by two. Which proves the square law. I don't think you can get away without there being some math to prove it's a square (and not, for example, a cube) but the area-of-a-triangle argument is about as intuitive as I can make it.